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A prismatic member with an area of cross-section ‘A’ is subjected to a tensile load ‘P,’ then the maximum shear stress and its inclination with the direction of load, respectively are-
- a)P/A and 60°
- b)P/2A and 45°
- c)P/2A and 60°
- d)P/A and 45°
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A prismatic member with an area of cross-section ‘A’ is subjected to ...
Normal stress in the direction of load =PA
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In the case of uniaxial stress, maximum principal stress σ1 and minimum principal stress σ2 will be PA and zero, respectively.
Maximum shear stress (\tau) 
Plane of maximum shear stress, 
tan2θ=∞,⇒θ=45∘
∴ The maximum shear stress and its inclination with the direction of load, respectively, are P/2A and 45°.
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A prismatic member with an area of cross-section ‘A’ is subjected to ...
Prismatic Member Under Tensile Load
- A prismatic member is a structural component that has a uniform cross-section throughout its length.
- When a prismatic member is subjected to a tensile load 'P', the stress induced in the member is given by σ = P/A, where A is the area of cross-section of the member.
- The stress is distributed uniformly across the cross-section of the member.
Maximum Shear Stress and its Inclination
- When a prismatic member is subjected to a tensile load, there is no shear stress in the member along the longitudinal direction.
- However, there is a shear stress induced in the member along the transverse direction.
- The maximum shear stress induced in the member is given by τ_max = P/2A.
- This shear stress is maximum at the neutral axis of the cross-section.
- The inclination of the maximum shear stress with the direction of load is 45°, which is the angle between the neutral axis and the plane of maximum shear stress.
Answer Explanation
- Option 'A' is incorrect because it gives the inclination of maximum shear stress as 60°, which is incorrect.
- Option 'C' is incorrect because it gives the maximum shear stress as P/A, which is incorrect.
- Option 'D' is incorrect because it gives the inclination of maximum shear stress as 45°, which is correct, but it gives the maximum shear stress as P/A, which is incorrect.
- Option 'B' is correct because it gives the maximum shear stress as P/2A, which is correct, and it gives the inclination of maximum shear stress as 45°, which is also correct.
- A prismatic member is a structural component that has a uniform cross-section throughout its length.
- When a prismatic member is subjected to a tensile load 'P', the stress induced in the member is given by σ = P/A, where A is the area of cross-section of the member.
- The stress is distributed uniformly across the cross-section of the member.
Maximum Shear Stress and its Inclination
- When a prismatic member is subjected to a tensile load, there is no shear stress in the member along the longitudinal direction.
- However, there is a shear stress induced in the member along the transverse direction.
- The maximum shear stress induced in the member is given by τ_max = P/2A.
- This shear stress is maximum at the neutral axis of the cross-section.
- The inclination of the maximum shear stress with the direction of load is 45°, which is the angle between the neutral axis and the plane of maximum shear stress.
Answer Explanation
- Option 'A' is incorrect because it gives the inclination of maximum shear stress as 60°, which is incorrect.
- Option 'C' is incorrect because it gives the maximum shear stress as P/A, which is incorrect.
- Option 'D' is incorrect because it gives the inclination of maximum shear stress as 45°, which is correct, but it gives the maximum shear stress as P/A, which is incorrect.
- Option 'B' is correct because it gives the maximum shear stress as P/2A, which is correct, and it gives the inclination of maximum shear stress as 45°, which is also correct.
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A prismatic member with an area of cross-section ‘A’ is subjected to a tensile load ‘P,’ then the maximum shear stress and its inclination with the direction of load, respectively are-a)P/A and 60°b)P/2A and 45°c)P/2A and 60°d)P/A and 45°Correct answer is option 'B'. Can you explain this answer?
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A prismatic member with an area of cross-section ‘A’ is subjected to a tensile load ‘P,’ then the maximum shear stress and its inclination with the direction of load, respectively are-a)P/A and 60°b)P/2A and 45°c)P/2A and 60°d)P/A and 45°Correct answer is option 'B'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about A prismatic member with an area of cross-section ‘A’ is subjected to a tensile load ‘P,’ then the maximum shear stress and its inclination with the direction of load, respectively are-a)P/A and 60°b)P/2A and 45°c)P/2A and 60°d)P/A and 45°Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A prismatic member with an area of cross-section ‘A’ is subjected to a tensile load ‘P,’ then the maximum shear stress and its inclination with the direction of load, respectively are-a)P/A and 60°b)P/2A and 45°c)P/2A and 60°d)P/A and 45°Correct answer is option 'B'. Can you explain this answer?.
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A prismatic member with an area of cross-section ‘A’ is subjected to a tensile load ‘P,’ then the maximum shear stress and its inclination with the direction of load, respectively are-a)P/A and 60°b)P/2A and 45°c)P/2A and 60°d)P/A and 45°Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A prismatic member with an area of cross-section ‘A’ is subjected to a tensile load ‘P,’ then the maximum shear stress and its inclination with the direction of load, respectively are-a)P/A and 60°b)P/2A and 45°c)P/2A and 60°d)P/A and 45°Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A prismatic member with an area of cross-section ‘A’ is subjected to a tensile load ‘P,’ then the maximum shear stress and its inclination with the direction of load, respectively are-a)P/A and 60°b)P/2A and 45°c)P/2A and 60°d)P/A and 45°Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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