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If the net amount of irrigation is 8 cm and field efficiency is 75%, the gross amount of water to be applied to the field will be
  • a)
    10.66 cm
  • b)
    8.75 cm
  • c)
    10.66 mm
  • d)
    8.75 mm
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If the net amount of irrigation is 8 cm and field efficiency is 75%, ...
Gross Irrigation Requirement, G|R=Net Irrigation Requirement(NIR) / field efficiency
The gross amount of water to be applied to the field will be
G|R = 8cm/0.75= 10.67 cm
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Community Answer
If the net amount of irrigation is 8 cm and field efficiency is 75%, ...
Gross Amount of Water Applied to the Field

To find the gross amount of water to be applied to the field, we need to understand the concept of field efficiency and net irrigation.

Field Efficiency

Field efficiency is a measure of how effectively the irrigation water is used by the field. It represents the percentage of water that is effectively used by the crops and does not get wasted or lost.

Field Efficiency (%) = (Net Irrigation / Gross Irrigation) * 100

Net Irrigation

Net irrigation is the amount of water that actually reaches the crops and is available for their use. It is the difference between the gross irrigation and the losses due to deep percolation, runoff, evaporation, and other factors.

Net Irrigation = Gross Irrigation - (Losses due to deep percolation, runoff, evaporation, etc.)

Calculating the Gross Amount of Water Applied

Given that the net amount of irrigation is 8 cm and the field efficiency is 75%, we can calculate the gross amount of water applied using the formula for field efficiency.

Field Efficiency = (Net Irrigation / Gross Irrigation) * 100

Substituting the given values:

75 = (8 / Gross Irrigation) * 100

Simplifying the equation:

0.75 = 8 / Gross Irrigation

Cross-multiplying:

Gross Irrigation = 8 / 0.75

Gross Irrigation = 10.6667 cm

Rounding off to two decimal places:

Gross Irrigation ≈ 10.67 cm

Therefore, the gross amount of water to be applied to the field is approximately 10.67 cm.

Answer

The correct answer is option A) 10.66 cm.
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If the net amount of irrigation is 8 cm and field efficiency is 75%, the gross amount of water to be applied to the field will bea)10.66 cmb)8.75 cmc)10.66 mmd)8.75 mmCorrect answer is option 'A'. Can you explain this answer?
Question Description
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