A person sitting in an open car moving at constant velocity throws a ...
Because the horizontal component of velocity are the same for both car and ball, so they cover equal horizontal distances in the given time interval.
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A person sitting in an open car moving at constant velocity throws a ...
Explanation:
When a person sitting in an open car throws a ball vertically up into the air, the ball follows a parabolic path due to the force of gravity acting on it. However, since the car is moving at a constant velocity, the ball also moves horizontally along with the car.
The correct answer to this question is option 'A', i.e., the ball falls exactly in the hand which threw it up. This is because the person and the ball are both moving at the same velocity as the car, and there is no force acting on the ball in the horizontal direction. Therefore, when the ball comes back down, it will fall straight down into the hand that threw it up.
To further understand this concept, we can break it down into the following points:
1. The ball is thrown vertically up into the air by the person sitting in the car.
2. The ball follows a parabolic path due to the force of gravity acting on it.
3. Since the car is moving at a constant velocity, the ball also moves horizontally along with the car.
4. However, there is no force acting on the ball in the horizontal direction, so it will continue to move with the car at the same velocity.
5. When the ball reaches the maximum height of its parabolic path, it momentarily stops moving vertically and begins to fall back down towards the ground.
6. Since the car and the person are still moving at the same velocity, the ball will fall straight back down into the hand that threw it up.
Therefore, the ball falls exactly in the hand which threw it up.