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Three charge q, Q and 4q are placed in a straight line of length l at points distant 0, 1/2
and l respectively from one end. In order to make the net froce on q zero, the charge Q must be equal to
and l respectively from one end. In order to make the net froce on q zero, the charge Q must be equal to
- a)–q
- b)– 2q
- c)-q/2
- d)q
Correct answer is option 'A'. Can you explain this answer?
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Three charge q, Q and 4q are placed in a straight line of length l at ...
To find the charge Q that will make the net force on q zero, we need to consider the forces exerted by each charge on q.
The force exerted by a charge on another charge is given by Coulomb's law:
F = k * (q1 * q2) / r^2
Where F is the force, k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between the charges.
In this case, q is at a distance of 0 from itself, a distance of 1/2 from Q, and a distance of l from 4q.
The force exerted by q on itself is zero, as there is no distance between them.
The force exerted by Q on q is given by:
F_Q = k * (q * Q) / (1/2)^2
= 4k * (q * Q)
The force exerted by 4q on q is given by:
F_4q = k * (q * 4q) / l^2
= 4k * (q^2) / l^2
For the net force on q to be zero, the forces exerted by Q and 4q must be equal in magnitude and opposite in direction:
F_Q = -F_4q
4k * (q * Q) = -4k * (q^2) / l^2
Simplifying, we can cancel out the 4k and q terms:
Q = -q / l^2
So the charge Q must be equal to -q divided by the square of the length l.
The force exerted by a charge on another charge is given by Coulomb's law:
F = k * (q1 * q2) / r^2
Where F is the force, k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between the charges.
In this case, q is at a distance of 0 from itself, a distance of 1/2 from Q, and a distance of l from 4q.
The force exerted by q on itself is zero, as there is no distance between them.
The force exerted by Q on q is given by:
F_Q = k * (q * Q) / (1/2)^2
= 4k * (q * Q)
The force exerted by 4q on q is given by:
F_4q = k * (q * 4q) / l^2
= 4k * (q^2) / l^2
For the net force on q to be zero, the forces exerted by Q and 4q must be equal in magnitude and opposite in direction:
F_Q = -F_4q
4k * (q * Q) = -4k * (q^2) / l^2
Simplifying, we can cancel out the 4k and q terms:
Q = -q / l^2
So the charge Q must be equal to -q divided by the square of the length l.
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Three charge q, Q and 4q are placed in a straight line of length l at ...
(Fnet )q =0
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Three charge q, Q and 4q are placed in a straight line of length l at points distant 0, 1/2and l respectively from one end. In order to make the net froce on q zero, the charge Q must be equal toa)–qb)– 2qc)-q/2d)qCorrect answer is option 'A'. Can you explain this answer?
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Three charge q, Q and 4q are placed in a straight line of length l at points distant 0, 1/2and l respectively from one end. In order to make the net froce on q zero, the charge Q must be equal toa)–qb)– 2qc)-q/2d)qCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Three charge q, Q and 4q are placed in a straight line of length l at points distant 0, 1/2and l respectively from one end. In order to make the net froce on q zero, the charge Q must be equal toa)–qb)– 2qc)-q/2d)qCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Three charge q, Q and 4q are placed in a straight line of length l at points distant 0, 1/2and l respectively from one end. In order to make the net froce on q zero, the charge Q must be equal toa)–qb)– 2qc)-q/2d)qCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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