JEE Exam > JEE Questions > From a 200 m high tower, one ball is thrown u...
Start Learning for Free
From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest to
- a)12 s
- b)6 s
- c)2 s
- d)1 s
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
From a 200 m high tower, one ball is thrown upwards with speed of 10 m...
The ball thrown upward will lose velocity in 1s. It return back to thrown point in another 1 s with the same velocity as second. Thus the difference will be 2 s.
Most Upvoted Answer
From a 200 m high tower, one ball is thrown upwards with speed of 10 m...
Solution:
Given data:
Height of the tower, h = 200 m
Initial velocity of the balls, u = 10 m/s
Acceleration due to gravity, g = 9.8 m/s²
Time taken by the ball to reach the ground from the top of the tower:
Using the formula, h = ut + 0.5gt²
On substituting the given values, we get:
200 = 10t + 0.5×9.8×t²
Simplifying, we get:
4.9t² + 10t - 200 = 0
On solving this quadratic equation, we get:
t = 6.427 s (approx.)
Time taken by the ball thrown upwards to reach the ground:
The time taken by the ball thrown upwards to reach the maximum height can be calculated using the formula, v = u - gt, where v is the final velocity at the maximum height.
At the maximum height, the final velocity becomes zero.
So, v = 0 m/s
On substituting the given values, we get:
0 = 10 - 9.8t
t = 10/9.8 s
The time taken by the ball thrown upwards to reach the maximum height is 10/9.8 s.
The time taken by the ball thrown upwards to reach the ground from the maximum height can be calculated using the formula, h = ut - 0.5gt².
On substituting the given values, we get:
200 = 10×(10/9.8) - 0.5×9.8×(10/9.8)²
Simplifying, we get:
200 = 101/49 - 100/49
200 = 1/49t²
On solving this equation, we get:
t = √(200×49) = 14.14 s (approx.)
Therefore, the time difference between the two balls reaching the ground is:
14.14 - 6.427 = 7.713 s (approx.)
The nearest option to this value is 2 seconds, which is option (c).
Given data:
Height of the tower, h = 200 m
Initial velocity of the balls, u = 10 m/s
Acceleration due to gravity, g = 9.8 m/s²
Time taken by the ball to reach the ground from the top of the tower:
Using the formula, h = ut + 0.5gt²
On substituting the given values, we get:
200 = 10t + 0.5×9.8×t²
Simplifying, we get:
4.9t² + 10t - 200 = 0
On solving this quadratic equation, we get:
t = 6.427 s (approx.)
Time taken by the ball thrown upwards to reach the ground:
The time taken by the ball thrown upwards to reach the maximum height can be calculated using the formula, v = u - gt, where v is the final velocity at the maximum height.
At the maximum height, the final velocity becomes zero.
So, v = 0 m/s
On substituting the given values, we get:
0 = 10 - 9.8t
t = 10/9.8 s
The time taken by the ball thrown upwards to reach the maximum height is 10/9.8 s.
The time taken by the ball thrown upwards to reach the ground from the maximum height can be calculated using the formula, h = ut - 0.5gt².
On substituting the given values, we get:
200 = 10×(10/9.8) - 0.5×9.8×(10/9.8)²
Simplifying, we get:
200 = 101/49 - 100/49
200 = 1/49t²
On solving this equation, we get:
t = √(200×49) = 14.14 s (approx.)
Therefore, the time difference between the two balls reaching the ground is:
14.14 - 6.427 = 7.713 s (approx.)
The nearest option to this value is 2 seconds, which is option (c).
Free Test
FREE
| Start Free Test |
Community Answer
From a 200 m high tower, one ball is thrown upwards with speed of 10 m...
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer?
Question Description
From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer?.
From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer?.
Solutions for From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest toa)12 sb)6 sc)2 sd)1 sCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup