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The filament of a light bulb has surface area 64 mm2. The filament can be considered as a black body at temperature 2500 K emitting radiation like a point source when viewed from far. At night the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer tobe circular with radius 3 mm. Then(Take Stefan-Boltzmann constant = 5.67 × 10−8 Wm−2 K−4, Wien’s displacement constant = 2.90 × 10−3 m-K, Planck’s constant = 6.63 × 10−34 Js, speed of light in vacuum= 3.00 × 108 ms−1)-a)power radiated by the filament is in the range 642 W to 645 Wb)radiated power entering into one eye of the observer is in the range 3.15 × 10−8 W to 3.25 × 10−8 Wc)the wavelength corresponding to the maximum intensity of light is 1160 nmd)taking the average wavelength of emitted radiation to be 1740 nm, the total number of photons entering per second into one eye of the observer is in the range 2.75 × 1011 to 2.85 × 1011Correct answer is option 'B,C,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The filament of a light bulb has surface area 64 mm2. The filament can be considered as a black body at temperature 2500 K emitting radiation like a point source when viewed from far. At night the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer tobe circular with radius 3 mm. Then(Take Stefan-Boltzmann constant = 5.67 × 10−8 Wm−2 K−4, Wien’s displacement constant = 2.90 × 10−3 m-K, Planck’s constant = 6.63 × 10−34 Js, speed of light in vacuum= 3.00 × 108 ms−1)-a)power radiated by the filament is in the range 642 W to 645 Wb)radiated power entering into one eye of the observer is in the range 3.15 × 10−8 W to 3.25 × 10−8 Wc)the wavelength corresponding to the maximum intensity of light is 1160 nmd)taking the average wavelength of emitted radiation to be 1740 nm, the total number of photons entering per second into one eye of the observer is in the range 2.75 × 1011 to 2.85 × 1011Correct answer is option 'B,C,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The filament of a light bulb has surface area 64 mm2. The filament can be considered as a black body at temperature 2500 K emitting radiation like a point source when viewed from far. At night the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer tobe circular with radius 3 mm. Then(Take Stefan-Boltzmann constant = 5.67 × 10−8 Wm−2 K−4, Wien’s displacement constant = 2.90 × 10−3 m-K, Planck’s constant = 6.63 × 10−34 Js, speed of light in vacuum= 3.00 × 108 ms−1)-a)power radiated by the filament is in the range 642 W to 645 Wb)radiated power entering into one eye of the observer is in the range 3.15 × 10−8 W to 3.25 × 10−8 Wc)the wavelength corresponding to the maximum intensity of light is 1160 nmd)taking the average wavelength of emitted radiation to be 1740 nm, the total number of photons entering per second into one eye of the observer is in the range 2.75 × 1011 to 2.85 × 1011Correct answer is option 'B,C,D'. Can you explain this answer?.

Solutions for The filament of a light bulb has surface area 64 mm2. The filament can be considered as a black body at temperature 2500 K emitting radiation like a point source when viewed from far. At night the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer tobe circular with radius 3 mm. Then(Take Stefan-Boltzmann constant = 5.67 × 10−8 Wm−2 K−4, Wien’s displacement constant = 2.90 × 10−3 m-K, Planck’s constant = 6.63 × 10−34 Js, speed of light in vacuum= 3.00 × 108 ms−1)-a)power radiated by the filament is in the range 642 W to 645 Wb)radiated power entering into one eye of the observer is in the range 3.15 × 10−8 W to 3.25 × 10−8 Wc)the wavelength corresponding to the maximum intensity of light is 1160 nmd)taking the average wavelength of emitted radiation to be 1740 nm, the total number of photons entering per second into one eye of the observer is in the range 2.75 × 1011 to 2.85 × 1011Correct answer is option 'B,C,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The filament of a light bulb has surface area 64 mm2. The filament can be considered as a black body at temperature 2500 K emitting radiation like a point source when viewed from far. At night the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer tobe circular with radius 3 mm. Then(Take Stefan-Boltzmann constant = 5.67 × 10−8 Wm−2 K−4, Wien’s displacement constant = 2.90 × 10−3 m-K, Planck’s constant = 6.63 × 10−34 Js, speed of light in vacuum= 3.00 × 108 ms−1)-a)power radiated by the filament is in the range 642 W to 645 Wb)radiated power entering into one eye of the observer is in the range 3.15 × 10−8 W to 3.25 × 10−8 Wc)the wavelength corresponding to the maximum intensity of light is 1160 nmd)taking the average wavelength of emitted radiation to be 1740 nm, the total number of photons entering per second into one eye of the observer is in the range 2.75 × 1011 to 2.85 × 1011Correct answer is option 'B,C,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The filament of a light bulb has surface area 64 mm2. The filament can be considered as a black body at temperature 2500 K emitting radiation like a point source when viewed from far. At night the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer tobe circular with radius 3 mm. Then(Take Stefan-Boltzmann constant = 5.67 × 10−8 Wm−2 K−4, Wien’s displacement constant = 2.90 × 10−3 m-K, Planck’s constant = 6.63 × 10−34 Js, speed of light in vacuum= 3.00 × 108 ms−1)-a)power radiated by the filament is in the range 642 W to 645 Wb)radiated power entering into one eye of the observer is in the range 3.15 × 10−8 W to 3.25 × 10−8 Wc)the wavelength corresponding to the maximum intensity of light is 1160 nmd)taking the average wavelength of emitted radiation to be 1740 nm, the total number of photons entering per second into one eye of the observer is in the range 2.75 × 1011 to 2.85 × 1011Correct answer is option 'B,C,D'. Can you explain this answer?, a detailed solution for The filament of a light bulb has surface area 64 mm2. The filament can be considered as a black body at temperature 2500 K emitting radiation like a point source when viewed from far. At night the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer tobe circular with radius 3 mm. Then(Take Stefan-Boltzmann constant = 5.67 × 10−8 Wm−2 K−4, Wien’s displacement constant = 2.90 × 10−3 m-K, Planck’s constant = 6.63 × 10−34 Js, speed of light in vacuum= 3.00 × 108 ms−1)-a)power radiated by the filament is in the range 642 W to 645 Wb)radiated power entering into one eye of the observer is in the range 3.15 × 10−8 W to 3.25 × 10−8 Wc)the wavelength corresponding to the maximum intensity of light is 1160 nmd)taking the average wavelength of emitted radiation to be 1740 nm, the total number of photons entering per second into one eye of the observer is in the range 2.75 × 1011 to 2.85 × 1011Correct answer is option 'B,C,D'. Can you explain this answer? has been provided alongside types of The filament of a light bulb has surface area 64 mm2. The filament can be considered as a black body at temperature 2500 K emitting radiation like a point source when viewed from far. At night the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer tobe circular with radius 3 mm. Then(Take Stefan-Boltzmann constant = 5.67 × 10−8 Wm−2 K−4, Wien’s displacement constant = 2.90 × 10−3 m-K, Planck’s constant = 6.63 × 10−34 Js, speed of light in vacuum= 3.00 × 108 ms−1)-a)power radiated by the filament is in the range 642 W to 645 Wb)radiated power entering into one eye of the observer is in the range 3.15 × 10−8 W to 3.25 × 10−8 Wc)the wavelength corresponding to the maximum intensity of light is 1160 nmd)taking the average wavelength of emitted radiation to be 1740 nm, the total number of photons entering per second into one eye of the observer is in the range 2.75 × 1011 to 2.85 × 1011Correct answer is option 'B,C,D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The filament of a light bulb has surface area 64 mm2. The filament can be considered as a black body at temperature 2500 K emitting radiation like a point source when viewed from far. At night the light bulb is observed from a distance of 100 m. Assume the pupil of the eyes of the observer tobe circular with radius 3 mm. Then(Take Stefan-Boltzmann constant = 5.67 × 10−8 Wm−2 K−4, Wien’s displacement constant = 2.90 × 10−3 m-K, Planck’s constant = 6.63 × 10−34 Js, speed of light in vacuum= 3.00 × 108 ms−1)-a)power radiated by the filament is in the range 642 W to 645 Wb)radiated power entering into one eye of the observer is in the range 3.15 × 10−8 W to 3.25 × 10−8 Wc)the wavelength corresponding to the maximum intensity of light is 1160 nmd)taking the average wavelength of emitted radiation to be 1740 nm, the total number of photons entering per second into one eye of the observer is in the range 2.75 × 1011 to 2.85 × 1011Correct answer is option 'B,C,D'. Can you explain this answer? tests, examples and also practice JEE tests.