Let M be a 3 × 3 invertible matrix with real entries and let I d...
X 2 matrix and N be a 2 x 4 matrix. In order to multiply these matrices, the number of columns in M must be equal to the number of rows in N. Since M has 2 columns and N has 2 rows, we can multiply these matrices.
To find the resulting matrix, we will use the formula for matrix multiplication. Let R be the resulting matrix, then:
R(i,j) = sum(M(i,k) * N(k,j)), where k goes from 1 to 2.
Therefore, R will be a 3 x 4 matrix. Each element in R is found by multiplying the corresponding row in M by the corresponding column in N, and taking the sum of the products. Here is the resulting matrix:
R = [ M(1,1) * N(1,1) + M(1,2) * N(2,1) , M(1,1) * N(1,2) + M(1,2) * N(2,2) , M(1,1) * N(1,3) + M(1,2) * N(2,3) , M(1,1) * N(1,4) + M(1,2) * N(2,4)
M(2,1) * N(1,1) + M(2,2) * N(2,1) , M(2,1) * N(1,2) + M(2,2) * N(2,2) , M(2,1) * N(1,3) + M(2,2) * N(2,3) , M(2,1) * N(1,4) + M(2,2) * N(2,4)
M(3,1) * N(1,1) + M(3,2) * N(2,1) , M(3,1) * N(1,2) + M(3,2) * N(2,2) , M(3,1) * N(1,3) + M(3,2) * N(2,3) , M(3,1) * N(1,4) + M(3,2) * N(2,4) ]
Note that each element in the resulting matrix is a sum of two products, where the first product comes from the corresponding row in M and the second product comes from the corresponding column in N.