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Three pipes x, y and z can fill a water tanker in 20, 25 and 30 minutes respectively. All the three pipes are opened to fill the tanker and if the pipe y is closed 2 minutes before the water tanker gets filled, then in how much time will the tank get filled?
  • a)
    8 minutes
  • b)
    10 minutes
  • c)
    324/37 minutes
  • d)
    312/37 minutes
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Three pipes x, y and z can fill a water tanker in 20, 25 and 30 minut...
Let the time after which the water tanker gets filled be 't' minutes.
In one minute pipe x can fill 1/20 part.
In t minutes, pipe x can then fill t/20 part.
Therefore, t/20 + t-2/25 + t/30 = 1
On solving, we get t = 324/37 minutes.
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Most Upvoted Answer
Three pipes x, y and z can fill a water tanker in 20, 25 and 30 minut...
To solve this problem, we can use the concept of rates. Let's assume that the capacity of the water tanker is 1 unit.

The rate at which pipe x can fill the tanker is 1/20 units per minute.
The rate at which pipe y can fill the tanker is 1/25 units per minute.
The rate at which pipe z can fill the tanker is 1/30 units per minute.

When all three pipes are opened, the combined rate at which they can fill the tanker is the sum of their individual rates:
1/20 + 1/25 + 1/30 = (6 + 4.8 + 4)/120 = 14.8/120 = 37/300 units per minute.

Now, let's assume that the tank gets filled in t minutes when all three pipes are opened.

In t minutes, the amount of water filled by pipe x is (1/20)t units.
In t minutes, the amount of water filled by pipe y is (1/25)(t-2) units. (Note that pipe y is closed 2 minutes before the tank gets filled)
In t minutes, the amount of water filled by pipe z is (1/30)t units.

According to the given condition, the sum of the amounts filled by each pipe should equal the capacity of the tank, which is 1 unit:

(1/20)t + (1/25)(t-2) + (1/30)t = 1

Multiplying through by 600 to get rid of the fractions, we have:

30t + 24(t-2) + 20t = 600

30t + 24t - 48 + 20t = 600

74t - 48 = 600

74t = 648

t = 648/74

t = 324/37 minutes

Therefore, the time taken to fill the tank when pipe y is closed 2 minutes before the tank gets filled is 324/37 minutes. Thus, the correct answer is option C.
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Three pipes x, y and z can fill a water tanker in 20, 25 and 30 minutes respectively. All the three pipes are opened to fill the tanker and if the pipe y is closed 2 minutes before the water tanker gets filled, then in how much time will the tank get filled?a)8 minutesb)10 minutesc)324/37 minutesd)312/37 minutesCorrect answer is option 'C'. Can you explain this answer?
Question Description
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