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Three pipes x, y and z can fill a water tanker in 20, 25 and 30 minutes respectively. All the three pipes are opened to fill the tanker, and if the pipe y is closed 2 minutes before the water tanker gets filled, then in how much time will the tank get filled?
- a)8 minutes
- b)10 minutes
- c)324/37 minutes
- d)312/37 minutes
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Three pipes x, y and z can fill a water tanker in 20, 25 and 30 minut...
Let the time after which the water tanker gets filled be 't' minutes.
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In one minute, pipe x can fill 1/20 part.
In t minutes, pipe x can then fill the t/20 part.
Therefore, t/20 + t - 2/25 + t/30 = 1
On solving, we get t = 324/37 minutes.
Most Upvoted Answer
Three pipes x, y and z can fill a water tanker in 20, 25 and 30 minut...
Calculation:
To find the time taken for the tanker to get filled when pipe y is closed 2 minutes before it gets filled, we need to calculate the total work done by all three pipes working together.
Let's assume the total work to fill the tanker is 300 units (LCM of 20, 25, and 30).
- Pipe x fills 300/20 = 15 units per minute.
- Pipe y fills 300/25 = 12 units per minute.
- Pipe z fills 300/30 = 10 units per minute.
Work done when all three pipes are open:
- Work done by all three pipes in 2 minutes = (15 + 12 + 10) * 2 = 74 units.
- Remaining work to be done = 300 - 74 = 226 units.
Now, when pipe y is closed, the work is done by pipe x and pipe z together.
- Combined rate of pipe x and z = 15 + 10 = 25 units per minute.
- Time taken to finish the remaining work = 226/25 = 9.04 minutes.
Therefore, the tank will get filled in 9.04 minutes, which is equivalent to 324/37 minutes.
So, the correct answer is option C - 324/37 minutes.
To find the time taken for the tanker to get filled when pipe y is closed 2 minutes before it gets filled, we need to calculate the total work done by all three pipes working together.
Let's assume the total work to fill the tanker is 300 units (LCM of 20, 25, and 30).
- Pipe x fills 300/20 = 15 units per minute.
- Pipe y fills 300/25 = 12 units per minute.
- Pipe z fills 300/30 = 10 units per minute.
Work done when all three pipes are open:
- Work done by all three pipes in 2 minutes = (15 + 12 + 10) * 2 = 74 units.
- Remaining work to be done = 300 - 74 = 226 units.
Now, when pipe y is closed, the work is done by pipe x and pipe z together.
- Combined rate of pipe x and z = 15 + 10 = 25 units per minute.
- Time taken to finish the remaining work = 226/25 = 9.04 minutes.
Therefore, the tank will get filled in 9.04 minutes, which is equivalent to 324/37 minutes.
So, the correct answer is option C - 324/37 minutes.
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Three pipes x, y and z can fill a water tanker in 20, 25 and 30 minutes respectively. All the three pipes are opened to fill the tanker, and if the pipe y is closed 2 minutes before the water tanker gets filled, then in how much time will the tank get filled?a)8 minutesb)10 minutesc)324/37 minutesd)312/37 minutesCorrect answer is option 'C'. Can you explain this answer?
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