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1. The Calcutta Mail left Mumbai at 9 PM sharp, Two hours later, the Geetanjali Express started from Mumbai in the same direction. The Geetanjali Ex press overtook the Calcutta Mail at 5 AM on the next morning. Find the average speed of the two trains over this journey, if the sum of their average speeds is 140 km/h. (a) 68.57 km/h?
Most Upvoted Answer
1. The Calcutta Mail left Mumbai at 9 PM sharp, Two hours later, the G...
Solution:

Given,
The Calcutta Mail left Mumbai at 9 PM sharp.
Two hours later, the Geetanjali Express started from Mumbai in the same direction.
The Geetanjali Express overtook the Calcutta Mail at 5 AM on the next morning.
The sum of their average speeds is 140 km/h.

To find:
The average speed of the two trains over this journey.

Let's assume,
The speed of Calcutta Mail be x km/h.
The speed of Geetanjali Express be y km/h.

Time taken by Calcutta Mail = 8 hours (9 PM to 5 AM)
Time taken by Geetanjali Express = 10 hours (11 PM to 9 AM)

Distance travelled by Calcutta Mail = x * 8 km
Distance travelled by Geetanjali Express = y * 10 km

Total distance travelled by both trains = x * 8 + y * 10 km

According to the question,
x + y = 140 km/h

Also, the Geetanjali Express overtook the Calcutta Mail, i.e.,
Distance travelled by Geetanjali Express = Distance travelled by Calcutta Mail

y * 10 = x * 8

Solving these two equations, we get
x = 68 km/h and y = 72 km/h

Therefore, the average speed of the two trains over this journey is
(68 + 72) / 2 = 70 km/h

Hence, the average speed of the two trains over this journey is 70 km/h.
Community Answer
1. The Calcutta Mail left Mumbai at 9 PM sharp, Two hours later, the G...
68.57km/h
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1. The Calcutta Mail left Mumbai at 9 PM sharp, Two hours later, the Geetanjali Express started from Mumbai in the same direction. The Geetanjali Ex press overtook the Calcutta Mail at 5 AM on the next morning. Find the average speed of the two trains over this journey, if the sum of their average speeds is 140 km/h. (a) 68.57 km/h?
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