Solution for the pair of equations:

To solve the pair of equations, we need to use the method of elimination.

1. Eliminating y:

Multiplying the first equation by 15 and the second equation by 27, we get:

15(1/16x) + 15(1/15y) = 15(9/20)
27(1/20x) - 27(1/27y) = 27(4/45)

Simplifying:

15/16x + y = 27/4
27/540x - 20/540y = 4/45

Multiplying the second equation by -1 and adding it to the first equation, we eliminate y:

15/16x + y = 27/4
-20/540x + 20/729y = -4/45

15/16x - 20/540x = 27/4 - 4/45

Simplifying:

-135/1080x = 283/180

x = -283/135

2. Solving for y:

Substituting x = -283/135 in the first equation:

1/16(-283/135) + 1/15y = 9/20

Simplifying:

-283/2160 + 1/15y = 9/20

1/15y = 9/20 + 283/2160

1/15y = 1409/5400

y = 1400/27

Therefore, the solution for the pair of equations is:

x = -283/135 and y = 1400/27

Explanation:

The solution of a pair of equations represents the values of x and y that satisfy both equations simultaneously. To find the solution, we use the method of elimination, which involves multiplying one or both equations by a constant to eliminate one of the variables. In this case, we multiplied the first equation by 15 and the second equation by 27 to eliminate y. Then, we added the two equations to eliminate y and solve for x. Finally, we substituted x in one of the equations to solve for y.