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If 2^(2x 3)-3^2×2^x 1=0 then the values of x are?
Most Upvoted Answer
If 2^(2x 3)-3^2×2^x 1=0 then the values of x are?
Explanation:
To solve the given equation, we can use the algebraic identity a^2 - b^2 = (a+b)(a-b)
Solution:
2^(2x 3) - 3^2 × 2^x 1 = 0
We can rewrite 3^2 as (2+1)^2 = 2^2 + 2×2×1 + 1^2 = 4 + 4 + 1 = 9
Substituting this value, we get:
2^(2x 3) - 9 × 2^x 1 = 0
We can rewrite this equation as:
(2^x3)^2 - (3×2^x1)^2 = 0
Using the algebraic identity a^2 - b^2 = (a+b)(a-b), we get:
(2^x3 + 3×2^x1)(2^x3 - 3×2^x1) = 0
Now we have two equations:
2^x3 + 3×2^x1 = 0
2^x3 - 3×2^x1 = 0
Solving for x in each of these equations, we get:
x = -3/2 or x = log2(3)/log2(2) = 1.585
Therefore, the values of x that satisfy the given equation are x = -3/2 or x = 1.585.
Final Answer:
The values of x that satisfy the given equation are x = -3/2 or x = 1.585.
Community Answer
If 2^(2x 3)-3^2×2^x 1=0 then the values of x are?
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If 2^(2x 3)-3^2×2^x 1=0 then the values of x are?
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If 2^(2x 3)-3^2×2^x 1=0 then the values of x are? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If 2^(2x 3)-3^2×2^x 1=0 then the values of x are? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 2^(2x 3)-3^2×2^x 1=0 then the values of x are?.
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