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How many gram of sodium (atomic mass 23 u) is required to prepare one mole of ethane from methyl chloride by Wurtz reaction?
  • a)
    2
  • b)
    23
  • c)
    11.5
  • d)
    46
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
How many gram of sodium (atomic mass 23 u) is required to prepare one...
The Wortz reaction between methyl chloride and sodium metal in presence of dry ether can be written as
⇒ 2 moles of sodium metal reacts to give 1 mole of ethane.
Also,
1 mole of Na metal = 23 g
∴ 2 motesol Na metal = 23x 2 = 46g
Thus, 46 g of sodium is required to prepare one mole of ethane from methyl chloride by Wurtz reaction.
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How many gram of sodium (atomic mass 23 u) is required to prepare one...
Calculating the Grams of Sodium Required for Wurtz Reaction
To prepare one mole of ethane from methyl chloride by Wurtz reaction, the reaction can be represented as follows:
2CH3Cl + 2Na -> C2H6 + 2NaCl

Step 1: Molar Ratio
From the balanced chemical equation, we can see that 2 moles of sodium (Na) are required to produce 1 mole of ethane (C2H6).

Step 2: Molar Mass
The molar mass of sodium is 23 g/mol.

Step 3: Calculating the Grams of Sodium Required
To find the grams of sodium required to produce 1 mole of ethane, we use the formula:
Grams = Number of moles x Molar mass
Grams = 1 mole x 23 g/mol
Grams = 23 grams
Therefore, 23 grams of sodium are required to prepare one mole of ethane from methyl chloride by Wurtz reaction. So, the correct answer is option 'D'.
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How many gram of sodium (atomic mass 23 u) is required to prepare one mole of ethane from methyl chloride by Wurtz reaction?a)2b)23c)11.5d)46Correct answer is option 'D'. Can you explain this answer?
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