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The integers 34041 and 32506 when divided by a three-digit integer n leave the same remainder. What is n?

  • a)
    289

  • b)
    367

  • c)
    453

  • d)
    307

Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The integers 34041 and 32506 when divided by a three-digit integer n l...
Let the common remainder be x.


32506 – x is divisible by n.


34041 – x is divisible by n.


Difference of (32506 – x) and (34041 – x) = (32506 – x) – (34041 – x)


⇒ 32506 – x – 34041 + x


⇒ 32506 – 34041


⇒ 1535 


Factors of 1535 = 1 × 5 × 307 × 1535


3-digit number = 307


⇒ n = 307


∴ The value of n is 307.
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Most Upvoted Answer
The integers 34041 and 32506 when divided by a three-digit integer n l...
Given: Two integers 34041 and 32506 leave the same remainder when divided by a three-digit integer n.

To Find: The value of n.

Solution:

Let the remainder be r.

So, we can write:

34041 ≡ r (mod n) ------------------- (1)

32506 ≡ r (mod n) ------------------- (2)

Subtracting (2) from (1), we get:

1525 ≡ 0 (mod n)

So, n must be a factor of 1525.

The factors of 1525 are:

1, 5, 25, 61, 305, 1525

Now, let's check which of these values of n satisfies the given condition.

For n = 1, remainder = 0 (not possible)

For n = 5, remainder = 1 (not possible)

For n = 25, remainder = 16 (not possible)

For n = 61, remainder = 50 (not possible)

For n = 305, remainder = 280 (not possible)

For n = 1525, remainder = 1416 (not possible)

So, none of the above values of n satisfies the given condition.

Hence, the correct value of n is not a factor of 1525.

Let's try another approach.

We can write:

34041 - r = nx ---------------- (3)

32506 - r = ny ---------------- (4)

where x and y are integers.

Subtracting (4) from (3), we get:

1535 = n(x - y)

So, n must be a factor of 1535.

The factors of 1535 are:

1, 5, 7, 11, 35, 55, 77, 385, 539, 847, 1535

Now, let's check which of these values of n satisfies the given condition.

For n = 1, remainder = 0 (not possible)

For n = 5, remainder = 1 (not possible)

For n = 7, remainder = 6 (not possible)

For n = 11, remainder = 10 (not possible)

For n = 35, remainder = 16 (not possible)

For n = 55, remainder = 26 (not possible)

For n = 77, remainder = 10 (not possible)

For n = 385, remainder = 231 (not possible)

For n = 539, remainder = 312 (not possible)

For n = 847, remainder = 512 (not possible)

For n = 1535, remainder = 1416 (not possible)

So, none of the above values of n satisfies the given condition.

Hence, the correct value of n is not a factor of 1535.

Let's try another approach.

We can write:

34041 = nk + r ----------------- (5)

32506 = nj + r ----------------- (6)

where k and j are integers.

Subtracting (6) from (5), we get:

1535 = n(k - j)

So, n must be a factor of 1535.

The factors of 1535 are:

1, 5, 7, 11, 35, 55, 77, 385, 539, 847, 1535

Now, let's check
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Community Answer
The integers 34041 and 32506 when divided by a three-digit integer n l...
The difference of the two numbers are 1535 so we want to get to the number so, 1×1535 and 307×5 is 1535 and in the option there is only one number 307 which satisfied the condition
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The integers 34041 and 32506 when divided by a three-digit integer n leave the same remainder. What is n?a)289b)367c)453d)307Correct answer is option 'D'. Can you explain this answer?
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