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The probability of getting at most '6' when three cubical dice are thrown is a 5/54 C. 5/36 b. 5/72 d. 5/216?
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The probability of getting at most '6' when three cubical dice are thr...
Solution:

We can use the complementary probability to find the probability of getting at most '6' when three cubical dice are thrown.

Step 1: Find the probability of getting more than '6' in one throw of a die.

The probability of getting more than '6' in one throw of a die is zero because a die has only six faces numbered from 1 to 6.

Step 2: Find the probability of getting more than '6' in three throws of a die.

The probability of getting more than '6' in three throws of a die is also zero because a die has only six faces numbered from 1 to 6.

Step 3: Find the probability of getting at most '6' in three throws of a die.

The probability of getting at most '6' in three throws of a die is the complement of the probability of getting more than '6' in three throws of a die.

P(getting at most '6') = 1 - P(getting more than '6')
P(getting at most '6') = 1 - 0
P(getting at most '6') = 1

Step 4: Find the probability of getting at most '6' in three throws of three dice.

The probability of getting at most '6' in three throws of three dice is the cube of the probability of getting at most '6' in one throw of a die.

P(getting at most '6' in three throws of three dice) = (1/6)^3
P(getting at most '6' in three throws of three dice) = 1/216

Therefore, the probability of getting at most '6' when three cubical dice are thrown is 1/216.

Answer: d. 5/216
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The probability of getting at most '6' when three cubical dice are thr...
Answer is option C
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The probability of getting at most '6' when three cubical dice are thrown is a 5/54 C. 5/36 b. 5/72 d. 5/216?
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