Introduction:
In this problem, we are given that the number has two digits and the digit in the ten's place is 3 times the other digit.

Representation:
Let the tens digit be represented by 'x' and the units digit be represented by 'y'.

Equation:
From the problem statement, we know that:

x = 3y

Range of Possible Values:
The value of x can range from 1 to 9 since it is a tens digit. The value of y can range from 0 to 9 since it is a units digit.

Combinations of Possible Values:
Using the equation x = 3y, we can list all the possible combinations of x and y:

- x=3, y=1
- x=6, y=2
- x=9, y=3
- x=12, y=4 (not possible since the number has only two digits)
- x=15, y=5 (not possible since the number has only two digits)
- x=18, y=6 (not possible since the number has only two digits)
- x=21, y=7 (not possible since the number has only two digits)
- x=24, y=8 (not possible since the number has only two digits)
- x=27, y=9 (not possible since the number has only two digits)

Conclusion:
Therefore, the possible numbers are 31, 62, and 93.