A number consists of two digits. The digits in the ten’s place i...
Let the digit at Tens place be x
The digit at unit place be y
The Number is 10x + y
ACCORDING TO THE QUESTION :-
x = 3y ... eq. 01
According to the second condition :
10x + y - 54 = 10y + x
=> 9x - 9y = 54
=> 9(x - y) = 9 × 6
=> x - y = 6 ... eq.02
Now we can solve the Equation 01 and 02 by substitution Method :-
x - y = 6
=> 3y - y = 6 [ from eq.01 , x = 3y ]
=> 2y = 6
=> y = 3
Now we can substitute the value of y in eq. 01 to get value of x
x = 3y
=> x = 3 × 3
=> x = 9
Hence the number is
Hence the number is 10x + y = 90 + 3 = 93 (ANS)
View all questions of this test
A number consists of two digits. The digits in the ten’s place i...
Given Information:
- The number consists of two digits.
- The digit in the tens place is 3 times the digit in the units place.
- When 54 is subtracted from the number, the digits are reversed.
To find: The number
Solution:
Let the number be 10x + y, where x is the digit in the tens place and y is the digit in the units place.
From the given information, we know that:
- x = 3y (since the digit in the tens place is 3 times the digit in the units place)
- 10x + y - 54 = 10y + x (since when 54 is subtracted from the number, the digits are reversed)
Simplifying the second equation, we get:
10x + y - 54 = 10y + x
9x - 9y = 54
x - y = 6
Substituting x = 3y in the above equation, we get:
3y - y = 6
2y = 6
y = 3
Therefore, x = 3y = 9.
Hence, the number is 93, which is option (c).
Final Answer: Option (c) 93
A number consists of two digits. The digits in the ten’s place i...
Let the two digit number = 10x + y:"the ten's place is 3 times the digit in the unit place"x = 3y:"if 54 is subtracted from the number the digits are reversed."10x + y - 54 = 10y + x10x - x = 10y - y + 549x = 9y + 54simplify, divide by 9x = y + 6Replace x with 3y3y = y + 63y - y = 62y = 6y = 3thenx = 3(3)x = 9:93 is the number:Or if u go by logic
Check solution in the statement:"if 54 is subtracted from the number the digits are reversed."93 - 54 = 39
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