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Farmer moves along the boundary of a square field of side 10 m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position ? Physics can you explain? and say answer?
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Farmer moves along the boundary of a square field of side 10 m in 40s....
Understanding the Problem
The farmer moves along the boundary of a square field with the following details:
- Side of the square field: 10 m
- Time taken to complete one round: 40 s
The objective is to find the magnitude of the displacement after 2 minutes and 20 seconds.
Calculating the Perimeter of the Square
- The perimeter (P) of the square is calculated as:
- P = 4 x side = 4 x 10 m = 40 m
Finding the Distance Covered
- The farmer completes one full round (40 m) in 40 seconds.
- In 2 minutes and 20 seconds, which is 140 seconds:
- The number of rounds completed = 140 s / 40 s = 3.5 rounds
- Total distance covered = 3.5 x 40 m = 140 m
Determining the Position After 3.5 Rounds
- After 3 full rounds, the farmer returns to the starting point.
- In the remaining 0.5 round (20 seconds):
- The distance covered in 0.5 round = 20 m (half the perimeter).
Calculating the Displacement
- After 3.5 rounds, the farmer is at a point on the square:
- Starting at one corner, after 0.5 round, he reaches the midpoint of one side of the square.
- Displacement is the shortest distance from the initial position to the final position:
- From the corner to the midpoint of the side is 5 m.
Final Answer
The magnitude of displacement of the farmer at the end of 2 minutes and 20 seconds from his initial position is 5 meters.
The farmer moves along the boundary of a square field with the following details:
- Side of the square field: 10 m
- Time taken to complete one round: 40 s
The objective is to find the magnitude of the displacement after 2 minutes and 20 seconds.
Calculating the Perimeter of the Square
- The perimeter (P) of the square is calculated as:
- P = 4 x side = 4 x 10 m = 40 m
Finding the Distance Covered
- The farmer completes one full round (40 m) in 40 seconds.
- In 2 minutes and 20 seconds, which is 140 seconds:
- The number of rounds completed = 140 s / 40 s = 3.5 rounds
- Total distance covered = 3.5 x 40 m = 140 m
Determining the Position After 3.5 Rounds
- After 3 full rounds, the farmer returns to the starting point.
- In the remaining 0.5 round (20 seconds):
- The distance covered in 0.5 round = 20 m (half the perimeter).
Calculating the Displacement
- After 3.5 rounds, the farmer is at a point on the square:
- Starting at one corner, after 0.5 round, he reaches the midpoint of one side of the square.
- Displacement is the shortest distance from the initial position to the final position:
- From the corner to the midpoint of the side is 5 m.
Final Answer
The magnitude of displacement of the farmer at the end of 2 minutes and 20 seconds from his initial position is 5 meters.
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Farmer moves along the boundary of a square field of side 10 m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position ? Physics can you explain? and say answer?
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Farmer moves along the boundary of a square field of side 10 m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position ? Physics can you explain? and say answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Farmer moves along the boundary of a square field of side 10 m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position ? Physics can you explain? and say answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Farmer moves along the boundary of a square field of side 10 m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position ? Physics can you explain? and say answer?.
Farmer moves along the boundary of a square field of side 10 m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position ? Physics can you explain? and say answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Farmer moves along the boundary of a square field of side 10 m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position ? Physics can you explain? and say answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Farmer moves along the boundary of a square field of side 10 m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position ? Physics can you explain? and say answer?.
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