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A farmer moves along the boundary of a square field of side 10 m in 40 second what will be the magnitude displacement of farmer at the end of 2 minutes 20 second from his initial position ?
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A farmer moves along the boundary of a square field of side 10 m in 40...
Calculating the Displacement of the Farmer
- First, we need to find the distance covered by the farmer in 40 seconds.
- The perimeter of the square field is 40m (4 sides of 10m each).
- The farmer covers the entire perimeter in 40 seconds.
- Therefore, the distance covered by the farmer in 40 seconds is 40m.
Calculating the Speed of the Farmer
- Speed = Distance/Time
- Speed = 40m / 40s
- Speed = 1 m/s
Calculating the Displacement of the Farmer in 2 minutes 20 seconds
- 2 minutes 20 seconds is equivalent to 140 seconds.
- Since the farmer is moving along the boundary of the square field, his displacement will be the diagonal of the square.
- The diagonal of a square can be calculated using the formula: Diagonal = Side * sqrt(2)
- Diagonal = 10m * sqrt(2)
- Diagonal ≈ 14.14m
Conclusion
- The magnitude displacement of the farmer at the end of 2 minutes 20 seconds from his initial position is approximately 14.14 meters.
- This displacement represents the shortest distance between the initial and final positions of the farmer along the diagonal of the square field.
Community Answer
A farmer moves along the boundary of a square field of side 10 m in 40...
Calculation of Magnitude Displacement of Farmer
- Given Data:
- Side of the square field = 10 m
- Time taken to move along the boundary of the square field = 40 seconds
- Calculation of Speed:
- Speed = Distance / Time
- Distance of one side of the square field = 10 m
- Time taken to cover one side = 40 seconds
- Speed = 10 m / 40 s = 0.25 m/s
- Calculation of Total Distance Covered in 2 minutes 20 seconds:
- Total time = 2 minutes 20 seconds = 140 seconds
- Number of sides covered in 140 seconds = 140 / 40 = 3.5 sides
- Total distance covered = 3.5 * 10 m = 35 m
- Calculation of Magnitude Displacement:
- Magnitude Displacement is the straight line distance between initial and final positions
- In a square field, the diagonal is √2 times the side
- Diagonal of the square field = √2 * 10 = 10√2 m
- Magnitude Displacement = 10√2 m
Therefore, the magnitude displacement of the farmer at the end of 2 minutes 20 seconds from his initial position is 10√2 meters.
- Given Data:
- Side of the square field = 10 m
- Time taken to move along the boundary of the square field = 40 seconds
- Calculation of Speed:
- Speed = Distance / Time
- Distance of one side of the square field = 10 m
- Time taken to cover one side = 40 seconds
- Speed = 10 m / 40 s = 0.25 m/s
- Calculation of Total Distance Covered in 2 minutes 20 seconds:
- Total time = 2 minutes 20 seconds = 140 seconds
- Number of sides covered in 140 seconds = 140 / 40 = 3.5 sides
- Total distance covered = 3.5 * 10 m = 35 m
- Calculation of Magnitude Displacement:
- Magnitude Displacement is the straight line distance between initial and final positions
- In a square field, the diagonal is √2 times the side
- Diagonal of the square field = √2 * 10 = 10√2 m
- Magnitude Displacement = 10√2 m
Therefore, the magnitude displacement of the farmer at the end of 2 minutes 20 seconds from his initial position is 10√2 meters.
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A farmer moves along the boundary of a square field of side 10 m in 40 second what will be the magnitude displacement of farmer at the end of 2 minutes 20 second from his initial position ?
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A farmer moves along the boundary of a square field of side 10 m in 40 second what will be the magnitude displacement of farmer at the end of 2 minutes 20 second from his initial position ? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A farmer moves along the boundary of a square field of side 10 m in 40 second what will be the magnitude displacement of farmer at the end of 2 minutes 20 second from his initial position ? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A farmer moves along the boundary of a square field of side 10 m in 40 second what will be the magnitude displacement of farmer at the end of 2 minutes 20 second from his initial position ?.
A farmer moves along the boundary of a square field of side 10 m in 40 second what will be the magnitude displacement of farmer at the end of 2 minutes 20 second from his initial position ? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A farmer moves along the boundary of a square field of side 10 m in 40 second what will be the magnitude displacement of farmer at the end of 2 minutes 20 second from his initial position ? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A farmer moves along the boundary of a square field of side 10 m in 40 second what will be the magnitude displacement of farmer at the end of 2 minutes 20 second from his initial position ?.
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