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A farmer moves along the perimeter of a square field of side 10m in 40 seconds.what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
Verified Answer
A farmer moves along the perimeter of a square field of side 10m in 40...
Total distance 40m in 40 sec.
Total time taken by the farmer = 2 min 20 sec. =140 seconds.
Total rounds completed= 140/40=3.5 rounds
That means if the farmer starts from point A of the square field, he reaches point C.
Therefore, displacement is AC.
Assume ABC is a right angled triangle.
Therefore,
AC^2 = AB^2 +BC^2 
AC^2 = (10)^2 +(10)^2
AC^2 = 100+100
AC^2 = 200

AC = (200)^1/2
 
AC= 10 x (2)^1/2
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A farmer moves along the perimeter of a square field of side 10m in 40 seconds.what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
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A farmer moves along the perimeter of a square field of side 10m in 40 seconds.what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A farmer moves along the perimeter of a square field of side 10m in 40 seconds.what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A farmer moves along the perimeter of a square field of side 10m in 40 seconds.what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?.
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