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a farmer moves along the boundary of a square field of side 10m in 40 second.what will be the magnitude of displacement of the farmer at the end of 2 min 20s from his initial position?
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a farmer moves along the boundary of a square field of side 10m in 40 ...
Total distance 40m in 40 sec.Total time taken by the farmer = 2 min 20 sec. =140 seconds.Total rounds completed= 140/40=3.5 roundsThat means if the farmer starts from point A of the square field, he reaches point C.Therefore, displacement is AC.Assume ABC is a right angled triangle.Therefore,AC2= AB^2 +BC^2 AC2= (10)^2 +(10)^2AC2= 100+100AC2=200AC = root(200) AC= 10 root(2).
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a farmer moves along the boundary of a square field of side 10m in 40 second.what will be the magnitude of displacement of the farmer at the end of 2 min 20s from his initial position?
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a farmer moves along the boundary of a square field of side 10m in 40 second.what will be the magnitude of displacement of the farmer at the end of 2 min 20s from his initial position? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about a farmer moves along the boundary of a square field of side 10m in 40 second.what will be the magnitude of displacement of the farmer at the end of 2 min 20s from his initial position? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a farmer moves along the boundary of a square field of side 10m in 40 second.what will be the magnitude of displacement of the farmer at the end of 2 min 20s from his initial position?.
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