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For a Poisson variate X, P(X = 1) = P (X = 2). What is the mean of X?
  • a)
    1.00
  • b)
    1.50
  • c)
    2.00
  • d)
    2.50
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
For a Poisson variate X, P(X = 1) = P (X = 2). What is the mean of X?a...
Explanation:
To find the mean of a Poisson distribution, we need to use the formula:

Mean (μ) = λ

Where λ is the rate parameter of the Poisson distribution.

In this question, we are given that P(X = 1) = P(X = 2), which means that the probability of observing one event is the same as the probability of observing two events. Let's denote this probability as p:

P(X = 1) = p
P(X = 2) = p

We know that the sum of probabilities for all possible values of X in a Poisson distribution is equal to 1. Therefore, we can write the equation:

P(X = 0) + P(X = 1) + P(X = 2) + ...

Since P(X = 1) = P(X = 2), we can rewrite the equation as:

P(X = 0) + P(X = 1) + P(X = 1) + ...

Simplifying further:

P(X = 0) + 2P(X = 1) + ...

We can see that the sum of probabilities for all possible values of X will be greater than 1, which is not possible. Hence, the only way for this equation to hold true is if P(X = 0) = 0.

Now, we can use the formula for the mean of a Poisson distribution:

Mean (μ) = λ

Since P(X = 0) = 0, it means that the rate parameter λ is not equal to zero. Therefore, the mean of X is equal to λ, which is the rate parameter.

Hence, the correct answer is option 'C' (2.00).
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For a Poisson variate X, P(X = 1) = P (X = 2). What is the mean of X?a)1.00b)1.50c)2.00d)2.50Correct answer is option 'C'. Can you explain this answer?
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