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The equation 3x^2 mx n=0 has roots that are double that of equation x^2 10x 12=0 . what is the value of m n ?
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The equation 3x^2 mx n=0 has roots that are double that of equation x...
Solution:

Given, the equation 3x^2 + mx + n = 0 has roots that are double that of equation x^2 + 10x + 12 = 0.

Let the roots of equation x^2 + 10x + 12 = 0 be α and β.

Then, α + β = -10 and αβ = 12.

The roots of the equation 3x^2 + mx + n = 0 are double that of α and β.

Let the roots of equation 3x^2 + mx + n = 0 be 2α and 2β.

Then, 2α + 2β = -m/3 and 4αβ = n/3.

We know that α + β = -10 and αβ = 12.

Substituting the values in the above equations, we get:

2(-10) = -m/3 => m = 60

4(12) = n/3 => n = 48

Therefore, the value of m is 60 and the value of n is 48.

Hence, the solution.
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The equation 3x^2 mx n=0 has roots that are double that of equation x^2 10x 12=0 . what is the value of m n ?
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