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The equation 3x2 mx n = 0 has roots that are double that of the equation x2 10x 12 = 0. What is the value of m n? (a) 104 (b) 204 (c) 102 (d) 202?
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The equation 3x2 mx n = 0 has roots that are double that of the eq...
Solution:

Given that the roots of the equation 3x^2 - mx + n = 0 are double that of the equation x^2 - 10x + 12 = 0.

Let the roots of the equation x^2 - 10x + 12 = 0 be α and β.

Then, α + β = 10 and αβ = 12.

The roots of the equation 3x^2 - mx + n = 0 are double of α and β.

Therefore, the roots of the equation 3x^2 - mx + n = 0 are 2α and 2β.

Sum of roots of the equation 3x^2 - mx + n = 0 is given by - b/a.

Hence, 2α + 2β = - (-m)/3

=> α + β = - m/6

=> 10 = - m/6

=> m = -60

Product of roots of the equation 3x^2 - mx + n = 0 is given by c/a.

Hence, (2α)(2β) = n/3

=> 4αβ = n/3

=> 4(12) = n/3 (Substitute αβ = 12)

=> n = 144

Therefore, m + n = -60 + 144 = 84.

Hence, the value of m + n is 84.

Therefore, the correct option is (d) 202.

Hence, the value of m and n is 60 and 144 respectively.
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The equation 3x2 mx n = 0 has roots that are double that of the equation x2 10x 12 = 0. What is the value of m n? (a) 104 (b) 204 (c) 102 (d) 202?
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