All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
CAT Exam  >  CAT Questions  >  In the above multiplication, A, B, C, D, E, F... Start Learning for Free
SaveJoin the Discussion on the App
In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5. 
If it is known that D is twice that of F, answer the following questions
 
Q. Which digit corresponds to the alphabet "G"?
Enter -1 if the answer can't be determined.
    Correct answer is '7'. Can you explain this answer?
    FREE This question is part of
    Download PDF Attempt Test
    		Download PDF Attempt this Test
    Verified Answer
    In the above multiplication, A, B, C, D, E, F, G and H are the differe...
    Since none of the digits is divisible by 5, Digits can be 1,2,3,4,6,7,8 and 9 only.
    From the above we see that C + 0 = 6. Thus C = 6.
    Looking at the second digit of the product. Unit place of C +  C = B. Thus unit digit of 6+6(12) is 2. Thus B = 2.
    The product simplifies into 
    We observe that unit places of D × G = 6 The pair of digits which gives 6 at unit digits on their product are (1,6), (2,3), (2,8), (4,4), (4,9) (6,6) and (7,8). Since we already know that C = 6, B = 2  and  D ≠ G only remaining possible pairs are (4,9) and (7,8). 
    Thus (D,G) can be (4,9) or (9,4) or (7,8) or (8,7)
    Upon further observation, we see that FGAD × 2 = HFG6 which is a 4-digit number. Thus the maximum possible value of F = 4 (if F≥5 then the product will be at least 5- digit. Thus F = 1 or 3 or 4
    We are given that D=2×F Thus F = 4, D= 8 which leaves G =7
    The remaining alphabets are A, E and H. The remaining digits to be allocated are 1,3 and 9. 
    Since one of the numbers for the product is 27. Thus the final product E27H26 should be divisible by 27. Thus it should be divisible by 9 also. For a number to be divisible by 9, the sum of its digits has to be a multiple of 9
    Thus  E+2+7+H+2+6 = 9k or E + H = 9k−17 or E + H = 9k′ + 1 where k =  k′+2
    Thus E + H = 1 or 10
    E + H = 1 is not possible as both are positive digts. Thus E + H = 10 and it happens when (E,H) = (1,9) or (9,1). Thus it will mean that A = 3 is the only possible scenario. Now we know that the 2 numbers whose product is taken is  4738 and 27. We can input the values and get the following
    Thus we obtain the following allocation
    View all questions of this test
    Most Upvoted Answer
    In the above multiplication, A, B, C, D, E, F, G and H are the differe...
    Since none of the digits is divisible by 5, Digits can be 1,2,3,4,6,7,8 and 9 only.
    From the above we see that C + 0 = 6. Thus C = 6.
    Looking at the second digit of the product. Unit place of C +  C = B. Thus unit digit of 6+6(12) is 2. Thus B = 2.
    The product simplifies into 
    We observe that unit places of D × G = 6 The pair of digits which gives 6 at unit digits on their product are (1,6), (2,3), (2,8), (4,4), (4,9) (6,6) and (7,8). Since we already know that C = 6, B = 2  and  D ≠ G only remaining possible pairs are (4,9) and (7,8). 
    Thus (D,G) can be (4,9) or (9,4) or (7,8) or (8,7)
    Upon further observation, we see that FGAD × 2 = HFG6 which is a 4-digit number. Thus the maximum possible value of F = 4 (if F≥5 then the product will be at least 5- digit. Thus F = 1 or 3 or 4
    We are given that D=2×F Thus F = 4, D= 8 which leaves G =7
    The remaining alphabets are A, E and H. The remaining digits to be allocated are 1,3 and 9. 
    Since one of the numbers for the product is 27. Thus the final product E27H26 should be divisible by 27. Thus it should be divisible by 9 also. For a number to be divisible by 9, the sum of its digits has to be a multiple of 9
    Thus  E+2+7+H+2+6 = 9k or E + H = 9k−17 or E + H = 9k′ + 1 where k =  k′+2
    Thus E + H = 1 or 10
    E + H = 1 is not possible as both are positive digts. Thus E + H = 10 and it happens when (E,H) = (1,9) or (9,1). Thus it will mean that A = 3 is the only possible scenario. Now we know that the 2 numbers whose product is taken is  4738 and 27. We can input the values and get the following
    Thus we obtain the following allocation
    Free Test
    FREE
    Start Free Test
    		Start Free Test
    Community Answer
    In the above multiplication, A, B, C, D, E, F, G and H are the differe...
    Since none of the digits is divisible by 5, Digits can be 1,2,3,4,6,7,8 and 9 only.
    From the above we see that C + 0 = 6. Thus C = 6.
    Looking at the second digit of the product. Unit place of C +  C = B. Thus unit digit of 6+6(12) is 2. Thus B = 2.
    The product simplifies into 
    We observe that unit places of D × G = 6 The pair of digits which gives 6 at unit digits on their product are (1,6), (2,3), (2,8), (4,4), (4,9) (6,6) and (7,8). Since we already know that C = 6, B = 2  and  D ≠ G only remaining possible pairs are (4,9) and (7,8). 
    Thus (D,G) can be (4,9) or (9,4) or (7,8) or (8,7)
    Upon further observation, we see that FGAD × 2 = HFG6 which is a 4-digit number. Thus the maximum possible value of F = 4 (if F≥5 then the product will be at least 5- digit. Thus F = 1 or 3 or 4
    We are given that D=2×F Thus F = 4, D= 8 which leaves G =7
    The remaining alphabets are A, E and H. The remaining digits to be allocated are 1,3 and 9. 
    Since one of the numbers for the product is 27. Thus the final product E27H26 should be divisible by 27. Thus it should be divisible by 9 also. For a number to be divisible by 9, the sum of its digits has to be a multiple of 9
    Thus  E+2+7+H+2+6 = 9k or E + H = 9k−17 or E + H = 9k′ + 1 where k =  k′+2
    Thus E + H = 1 or 10
    E + H = 1 is not possible as both are positive digts. Thus E + H = 10 and it happens when (E,H) = (1,9) or (9,1). Thus it will mean that A = 3 is the only possible scenario. Now we know that the 2 numbers whose product is taken is  4738 and 27. We can input the values and get the following
    Thus we obtain the following allocation
    Attention CAT Students!
    To make sure you are not studying endlessly, EduRev has designed CAT study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CAT.
    < Previous Question Next Question >
    Explore Courses for CAT exam

    Similar CAT Doubts

    Group QuestionAnswer the following question based on the information given belowDarren Puppet, the richest person in the world, has ensured extra security for his files. He implements a security based on division algorithms in his passwords. The passwords contain n digits such that :I. It contains all digits from 1 to n, and all of them are used exactly once.II. The number formed by the first two digits is divisible by 2, the number formed by the first 3 digits is divisible by 3, and so on such that the n digit password is divisible by n. (For example, 123 is such a 3 digit password, 12 is divisible by 2 and 123 by 3).To remember which password he is using, Darren ranks all the passwords having certain number of digits in increasing order and hence by just knowing the number of digits and the rank, he is able to correctly enter the password. (For example, for 3 digits passwords, 123 has rank 1 and 321 has rank 2)It is known that he uses 6 digit passwords for leisure files, which are his most important files.Q. What is/are the possible values of the fourth digit of the password that he uses for leisure files? Correct answer is '6'. Can you explain this answer?

    Top Courses for CATView all

    Top Courses for CAT

    In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5.If it is known that D is twice that of F, answer the following questionsQ. Which digit corresponds to the alphabet "G"?Enter -1 if the answer cant be determined.Correct answer is '7'. Can you explain this answer?
    Question Description
    In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5.If it is known that D is twice that of F, answer the following questionsQ. Which digit corresponds to the alphabet "G"?Enter -1 if the answer cant be determined.Correct answer is '7'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5.If it is known that D is twice that of F, answer the following questionsQ. Which digit corresponds to the alphabet "G"?Enter -1 if the answer cant be determined.Correct answer is '7'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5.If it is known that D is twice that of F, answer the following questionsQ. Which digit corresponds to the alphabet "G"?Enter -1 if the answer cant be determined.Correct answer is '7'. Can you explain this answer?.
    Solutions for In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5.If it is known that D is twice that of F, answer the following questionsQ. Which digit corresponds to the alphabet "G"?Enter -1 if the answer cant be determined.Correct answer is '7'. Can you explain this answer? in English & in Hindi are available as part of our courses for CAT. Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free.
    Here you can find the meaning of In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5.If it is known that D is twice that of F, answer the following questionsQ. Which digit corresponds to the alphabet "G"?Enter -1 if the answer cant be determined.Correct answer is '7'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5.If it is known that D is twice that of F, answer the following questionsQ. Which digit corresponds to the alphabet "G"?Enter -1 if the answer cant be determined.Correct answer is '7'. Can you explain this answer?, a detailed solution for In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5.If it is known that D is twice that of F, answer the following questionsQ. Which digit corresponds to the alphabet "G"?Enter -1 if the answer cant be determined.Correct answer is '7'. Can you explain this answer? has been provided alongside types of In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5.If it is known that D is twice that of F, answer the following questionsQ. Which digit corresponds to the alphabet "G"?Enter -1 if the answer cant be determined.Correct answer is '7'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In the above multiplication, A, B, C, D, E, F, G and H are the different digits of number such that none of them is divisible by 5.If it is known that D is twice that of F, answer the following questionsQ. Which digit corresponds to the alphabet "G"?Enter -1 if the answer cant be determined.Correct answer is '7'. Can you explain this answer? tests, examples and also practice CAT tests.
    Explore Courses for CAT exam

    Top Courses for CAT

    Explore Courses

    Suggested Free Tests

    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev
    Get App
    © EduRev
    Education Revolution
    Follow Us
    Signup to see your scores go up within 7 days!
    Access 1000+ FREE Docs, Videos and Tests
    Takes less than 10 seconds to signup