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Determine the number of 7.5 m3 container required per week for waste collection after compaction for a colony of 200 house, 3 people per house. The generation rate is 0.6 kg/person/day. The compacted specific weight is 250 kg/m3.?
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Determine the number of 7.5 m3 container required per week for waste c...
Given data:
- Number of houses in the colony: 200
- Number of people per house: 3
- Generation rate: 0.6 kg/person/day
- Compacted specific weight: 250 kg/m3
Calculation:
Step 1: Calculate the total waste generation per day
Total number of people in the colony = Number of houses × Number of people per house
= 200 × 3 = 600
Total waste generation per day = Generation rate × Total number of people in the colony
= 0.6 kg/person/day × 600 = 360 kg/day
Step 2: Calculate the waste generation per week
Total waste generation per week = Total waste generation per day × 7 days
= 360 kg/day × 7 days = 2520 kg/week
Step 3: Calculate the volume of waste generated per week
Volume of waste generated per week = Total waste generation per week / Compacted specific weight
= 2520 kg/week / 250 kg/m3 = 10.08 m3/week
Step 4: Calculate the number of 7.5 m3 containers required
Number of 7.5 m3 containers required per week = Volume of waste generated per week / Volume of each container
= 10.08 m3/week / 7.5 m3/container ≈ 1.34 containers/week
Step 5: Round up to the nearest whole number
Since we cannot have fractional containers, we need to round up the number of containers required to the nearest whole number.
Number of 7.5 m3 containers required per week = 2 containers/week (rounded up)
Conclusion:
For waste collection after compaction for a colony of 200 houses, with 3 people per house, and a waste generation rate of 0.6 kg/person/day, it is estimated that approximately 2 containers of 7.5 m3 each would be required per week.
- Number of houses in the colony: 200
- Number of people per house: 3
- Generation rate: 0.6 kg/person/day
- Compacted specific weight: 250 kg/m3
Calculation:
Step 1: Calculate the total waste generation per day
Total number of people in the colony = Number of houses × Number of people per house
= 200 × 3 = 600
Total waste generation per day = Generation rate × Total number of people in the colony
= 0.6 kg/person/day × 600 = 360 kg/day
Step 2: Calculate the waste generation per week
Total waste generation per week = Total waste generation per day × 7 days
= 360 kg/day × 7 days = 2520 kg/week
Step 3: Calculate the volume of waste generated per week
Volume of waste generated per week = Total waste generation per week / Compacted specific weight
= 2520 kg/week / 250 kg/m3 = 10.08 m3/week
Step 4: Calculate the number of 7.5 m3 containers required
Number of 7.5 m3 containers required per week = Volume of waste generated per week / Volume of each container
= 10.08 m3/week / 7.5 m3/container ≈ 1.34 containers/week
Step 5: Round up to the nearest whole number
Since we cannot have fractional containers, we need to round up the number of containers required to the nearest whole number.
Number of 7.5 m3 containers required per week = 2 containers/week (rounded up)
Conclusion:
For waste collection after compaction for a colony of 200 houses, with 3 people per house, and a waste generation rate of 0.6 kg/person/day, it is estimated that approximately 2 containers of 7.5 m3 each would be required per week.
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Determine the number of 7.5 m3 container required per week for waste collection after compaction for a colony of 200 house, 3 people per house. The generation rate is 0.6 kg/person/day. The compacted specific weight is 250 kg/m3.?
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Determine the number of 7.5 m3 container required per week for waste collection after compaction for a colony of 200 house, 3 people per house. The generation rate is 0.6 kg/person/day. The compacted specific weight is 250 kg/m3.? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Determine the number of 7.5 m3 container required per week for waste collection after compaction for a colony of 200 house, 3 people per house. The generation rate is 0.6 kg/person/day. The compacted specific weight is 250 kg/m3.? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the number of 7.5 m3 container required per week for waste collection after compaction for a colony of 200 house, 3 people per house. The generation rate is 0.6 kg/person/day. The compacted specific weight is 250 kg/m3.?.
Determine the number of 7.5 m3 container required per week for waste collection after compaction for a colony of 200 house, 3 people per house. The generation rate is 0.6 kg/person/day. The compacted specific weight is 250 kg/m3.? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Determine the number of 7.5 m3 container required per week for waste collection after compaction for a colony of 200 house, 3 people per house. The generation rate is 0.6 kg/person/day. The compacted specific weight is 250 kg/m3.? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the number of 7.5 m3 container required per week for waste collection after compaction for a colony of 200 house, 3 people per house. The generation rate is 0.6 kg/person/day. The compacted specific weight is 250 kg/m3.?.
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