Solution A and solution B are 2 solutions of orange such that the conc...
The concentration of orange juice in solution A = 64%
The concentration of orange juice in solution B = 100-20 = 80%
The resultant solution obtained by mixing is of volume 20L out of which 6 L is water.
Quantity of orange juice = 20L - 6L =14L
Concentration of orange = 14/20 × 100% = 70%
As per question 0.64x + 0.8y = 0.7(x+y)
0.1y = 0.06x
x/y = 0.1/0.06 = 35
x = 5 and y = 3
3x + 2y = 3(5) + 2(3) = 15 + 6 = 21
View all questions of this test
Solution A and solution B are 2 solutions of orange such that the conc...
To solve this problem, we can set up a system of equations based on the given information.
Let's assume that the ratio of solution A to solution B is x:y. Therefore, the total volume of solution A will be (20*x/(x+y)) liters, and the total volume of solution B will be (20*y/(x+y)) liters.
We are given that the concentration of orange juice in solution A is 64%. This means that 64% of the total volume of solution A is orange juice.
Therefore, the volume of orange juice in solution A is (0.64 * (20*x/(x+y))) liters.
Similarly, the concentration of water in solution B is 20%. This means that 20% of the total volume of solution B is water.
Therefore, the volume of water in solution B is (0.2 * (20*y/(x+y))) liters.
We are also given that the total solution has 6 liters of water. Therefore, we can set up the following equation:
(0.2 * (20*y/(x+y))) = 6
Simplifying this equation, we get:
(4*y/(x+y)) = 6
4y = 6(x+y)
4y = 6x + 6y
2y = 6x
Now, we need to find the value of 3x^2 + 2y^2. Since we know that 2y = 6x, we can substitute this value into the equation:
3x^2 + 2y^2 = 3x^2 + 2(6x)^2
= 3x^2 + 2(36x^2)
= 3x^2 + 72x^2
= 75x^2
Therefore, the value of 3x^2 + 2y^2 is 75x^2.
Since x and y are co-prime, we can find the value of 3x^2 + 2y^2 by substituting the value of y from the equation 2y = 6x:
3x^2 + 2(3x)^2 = 3x^2 + 18x^2 = 21x^2
Therefore, the value of 3x^2 + 2y^2 is 21x^2.
Hence, the correct answer is option D) 21.
Solution A and solution B are 2 solutions of orange such that the conc...
Orange percentages :A : 64%B : 80% ( water % is given in question )Mixture : 70% ( from question 6L in 20L means 30% water ) Now A. B. 64. 80 70. 10. 6. = 10:6 = 5:3 ; x=5,Y=3 substitute in equation. Will get 21.
To make sure you are not studying endlessly, EduRev has designed CAT study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CAT.