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What is the minimum required diameter d (in cm) for a solid circular shaft if it is to transmit 40 HP at 600 RPM without exceeding an allowable shear stress of 27.57 MPa?
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What is the minimum required diameter d (in cm) for a solid circular s...
Calculating the Required Diameter of the Shaft
- Given data:
- Power (P) = 40 HP = 40 x 746 W (conversion to Watts) = 29840 W
- Speed (N) = 600 RPM
- Allowable shear stress (τ) = 27.57 MPa = 27.57 x 10^6 Pa
- Formula for power transmission in a shaft:
P = 2πNT/60
- Rearranging the formula for T (torque):
T = (60 x P) / (2πN)
- Substituting the values:
T = (60 x 29840) / (2π x 600) = 298400 / 3770.8 = 79.08 Nm
- Formula for shear stress in a solid circular shaft:
τ = 16T / (πd^3)
- Rearranging the formula for d (shaft diameter):
d = (16T / (πτ))^(1/3)
- Substituting the values:
d = (16 x 79.08 / (π x 27.57 x 10^6))^(1/3) = (1265.28 / 86506017.35)^(1/3) = 0.00001463 m
- Converting the diameter to cm:
d = 0.00001463 m x 100 cm/m = 0.001463 cm
Therefore, the minimum required diameter of the solid circular shaft to transmit 40 HP at 600 RPM without exceeding an allowable shear stress of 27.57 MPa is approximately 1.46 cm.
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What is the minimum required diameter d (in cm) for a solid circular shaft if it is to transmit 40 HP at 600 RPM without exceeding an allowable shear stress of 27.57 MPa?
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