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A project has six activities (A t o F ) w it h respective activity durations 7,5,6,6,8,4 days.The network has three path A-B, C-D and EF. All the activities can be crashed with the same crash cost per day.The number of activities that need to be crashed to reduce the project duration by 1 day is
[2005]
- a)1
- b)2
- c)3
- d)6
Correct answer is option 'C'. Can you explain this answer?
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A project has six activities (A t o F ) w it h respective activity dur...
Solution:
To reduce the project duration by 1 day, we need to crash the critical path activity with the least crash cost. Let's find the critical path and the crash cost of each activity.
Step 1: Draw the network diagram and find the earliest start time (EST) and earliest finish time (EFT) of each activity.
Activity A B C D E F
Duration 7 5 6 6 8 4
EST 0 7 0 6 7 12
EFT 7 12 6 12 15 16
Step 2: Find the latest start time (LST) and latest finish time (LFT) of each activity by working backward from the project end.
Activity A B C D E F
Duration 7 5 6 6 8 4
EST 0 7 0 6 7 12
EFT 7 12 6 12 15 16
LST 0 7 1 6 7 12
LFT 7 12 7 12 15 16
Step 3: Calculate the slack time of each activity by subtracting its duration from the difference between its LST and EST.
Activity A B C D E F
Duration 7 5 6 6 8 4
EST 0 7 0 6 7 12
EFT 7 12 6 12 15 16
LST 0 7 1 6 7 12
LFT 7 12 7 12 15 16
Slack 0 0 1 0 0 0
Step 4: Identify the critical path, which is the longest path with zero slack.
Critical path: A - B - E - F
Step 5: Calculate the crash cost of each activity by finding the difference between its normal duration and its crash duration, divided by the number of days saved.
Activity A B C D E F
Duration 7 5 6 6 8 4
Crash cost per day ? ? ? ? ? ?
Normal duration 7 5 6 6 8 4
Crash duration ? ? ? ? ? ?
Crash cost ? ? ? ? ? ?
We do not have information about the crash duration or crash cost per day, so we cannot calculate the crash cost.
Step 6: To reduce the project duration by 1 day, we need to crash the critical path activity with the least crash cost.
The critical path activities are A, B, E, and F. To reduce the project duration by 1 day, we need to crash at least one of these activities. Since we do not have information about the crash cost, we cannot determine which activity to crash. However, we can say that we need to crash at least 3 activities to reduce the project duration by 1 day because if we crash only one or two activities, the project duration will not be reduced by 1 day.
To reduce the project duration by 1 day, we need to crash the critical path activity with the least crash cost. Let's find the critical path and the crash cost of each activity.
Step 1: Draw the network diagram and find the earliest start time (EST) and earliest finish time (EFT) of each activity.
Activity A B C D E F
Duration 7 5 6 6 8 4
EST 0 7 0 6 7 12
EFT 7 12 6 12 15 16
Step 2: Find the latest start time (LST) and latest finish time (LFT) of each activity by working backward from the project end.
Activity A B C D E F
Duration 7 5 6 6 8 4
EST 0 7 0 6 7 12
EFT 7 12 6 12 15 16
LST 0 7 1 6 7 12
LFT 7 12 7 12 15 16
Step 3: Calculate the slack time of each activity by subtracting its duration from the difference between its LST and EST.
Activity A B C D E F
Duration 7 5 6 6 8 4
EST 0 7 0 6 7 12
EFT 7 12 6 12 15 16
LST 0 7 1 6 7 12
LFT 7 12 7 12 15 16
Slack 0 0 1 0 0 0
Step 4: Identify the critical path, which is the longest path with zero slack.
Critical path: A - B - E - F
Step 5: Calculate the crash cost of each activity by finding the difference between its normal duration and its crash duration, divided by the number of days saved.
Activity A B C D E F
Duration 7 5 6 6 8 4
Crash cost per day ? ? ? ? ? ?
Normal duration 7 5 6 6 8 4
Crash duration ? ? ? ? ? ?
Crash cost ? ? ? ? ? ?
We do not have information about the crash duration or crash cost per day, so we cannot calculate the crash cost.
Step 6: To reduce the project duration by 1 day, we need to crash the critical path activity with the least crash cost.
The critical path activities are A, B, E, and F. To reduce the project duration by 1 day, we need to crash at least one of these activities. Since we do not have information about the crash cost, we cannot determine which activity to crash. However, we can say that we need to crash at least 3 activities to reduce the project duration by 1 day because if we crash only one or two activities, the project duration will not be reduced by 1 day.
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A project has six activities (A t o F ) w it h respective activity durations 7,5,6,6,8,4 days.The network has three path A-B, C-D and EF. All the activities can be crashed with the same crash cost per day.The number of activities that need to be crashed to reduce the project duration by 1 day is[2005]a)1b)2c)3d)6Correct answer is option 'C'. Can you explain this answer?
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A project has six activities (A t o F ) w it h respective activity durations 7,5,6,6,8,4 days.The network has three path A-B, C-D and EF. All the activities can be crashed with the same crash cost per day.The number of activities that need to be crashed to reduce the project duration by 1 day is[2005]a)1b)2c)3d)6Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A project has six activities (A t o F ) w it h respective activity durations 7,5,6,6,8,4 days.The network has three path A-B, C-D and EF. All the activities can be crashed with the same crash cost per day.The number of activities that need to be crashed to reduce the project duration by 1 day is[2005]a)1b)2c)3d)6Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A project has six activities (A t o F ) w it h respective activity durations 7,5,6,6,8,4 days.The network has three path A-B, C-D and EF. All the activities can be crashed with the same crash cost per day.The number of activities that need to be crashed to reduce the project duration by 1 day is[2005]a)1b)2c)3d)6Correct answer is option 'C'. Can you explain this answer?.
A project has six activities (A t o F ) w it h respective activity durations 7,5,6,6,8,4 days.The network has three path A-B, C-D and EF. All the activities can be crashed with the same crash cost per day.The number of activities that need to be crashed to reduce the project duration by 1 day is[2005]a)1b)2c)3d)6Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A project has six activities (A t o F ) w it h respective activity durations 7,5,6,6,8,4 days.The network has three path A-B, C-D and EF. All the activities can be crashed with the same crash cost per day.The number of activities that need to be crashed to reduce the project duration by 1 day is[2005]a)1b)2c)3d)6Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A project has six activities (A t o F ) w it h respective activity durations 7,5,6,6,8,4 days.The network has three path A-B, C-D and EF. All the activities can be crashed with the same crash cost per day.The number of activities that need to be crashed to reduce the project duration by 1 day is[2005]a)1b)2c)3d)6Correct answer is option 'C'. Can you explain this answer?.
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