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8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined. In how many more days will the work be completed?
- a)5 days
- b)8 days
- c)6 days
- d)4 days
- e)9 days
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
8 men and 4 women-together can complete a piece of work in 6 days. Wo...
According to condition given, work of 1 man = work of 2 women or 1 man = 2 women
Therefore, 8 men + 4 women will be = 20 women
Since 20 women complete the work in 6 days, the work completed in 2 days by 20 women ( 8 men and 4 women) will be 1/3rd of the total work.
If 4 men leave and 4 women join
Total number of women now = 20 - (2 x 4) + 4 = 16
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Community Answer
8 men and 4 women-together can complete a piece of work in 6 days. Wo...
Given information:
- 8 men and 4 women can complete the work in 6 days.
- Work done by a man in one day is double the work done by a woman in one day.
To find:
- In how many more days will the work be completed after 2 days, when 4 men leave and 4 new women join?
Solution:
Let's assume that the work done by a woman in one day is x units.
Therefore, the work done by a man in one day is 2x units.
Work done by 8 men and 4 women in 1 day = (8 * 2x) + (4 * x) = 16x + 4x = 20x units
Work done by 8 men and 4 women in 2 days = 2 * (16x + 4x) = 40x units
Now, after 2 days, 4 men leave and 4 new women join.
So, the new team consists of 4 men and 8 women.
Work done by 4 men and 8 women in 1 day = (4 * 2x) + (8 * x) = 8x + 8x = 16x units
Let's assume that the work remaining after 2 days is R units.
So, the total work is R + 40x units.
Number of days required to complete the remaining work = (R + 40x) / (16x) = (R/16x) + 40/16 = (R/16x) + 5/2
Since R/16x represents the fraction of work remaining after 2 days, it is a value between 0 and 1.
Therefore, the additional number of days required to complete the work will be between 0 and 5/2.
Since the options given are in whole numbers of days, the only possible answer is 5 days.
Hence, the correct answer is option A) 5 days.
- 8 men and 4 women can complete the work in 6 days.
- Work done by a man in one day is double the work done by a woman in one day.
To find:
- In how many more days will the work be completed after 2 days, when 4 men leave and 4 new women join?
Solution:
Let's assume that the work done by a woman in one day is x units.
Therefore, the work done by a man in one day is 2x units.
Work done by 8 men and 4 women in 1 day = (8 * 2x) + (4 * x) = 16x + 4x = 20x units
Work done by 8 men and 4 women in 2 days = 2 * (16x + 4x) = 40x units
Now, after 2 days, 4 men leave and 4 new women join.
So, the new team consists of 4 men and 8 women.
Work done by 4 men and 8 women in 1 day = (4 * 2x) + (8 * x) = 8x + 8x = 16x units
Let's assume that the work remaining after 2 days is R units.
So, the total work is R + 40x units.
Number of days required to complete the remaining work = (R + 40x) / (16x) = (R/16x) + 40/16 = (R/16x) + 5/2
Since R/16x represents the fraction of work remaining after 2 days, it is a value between 0 and 1.
Therefore, the additional number of days required to complete the work will be between 0 and 5/2.
Since the options given are in whole numbers of days, the only possible answer is 5 days.
Hence, the correct answer is option A) 5 days.
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8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined. In how many more days will the work be completed?a)5 daysb)8 daysc)6 daysd)4 dayse)9 daysCorrect answer is option 'A'. Can you explain this answer?
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