NEET Exam  >  NEET Questions  >   For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr... Start Learning for Free
For the reaction:
[Cr(H2O)6]3+ + [SCN] → [Cr(H2O)5NCS]2+ + H2O
The rate law is: r = k[Cr(H2O)6]3+ + [SCN].
The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?
  • a)
    26 kcal mol–1
  • b)
    2.6 kcal mol–1
  • c)
    2600 kcal mol–1
  • d)
    260 kcal mol–1
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rat...
Use Arrhenius equation
T1 = 273 + 14 = 287 K,
T2 = 273 + 30 = 303 K
View all questions of this test
Most Upvoted Answer
For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rat...
Calculation of Activation Energy (Ea)

Given Data:
- k1 = 2.0 × 10^–6 L mol^–1 s^–1 (at 14 °C)
- k2 = 2.2 × 10^–5 L mol^–1 s^–1 (at 30 °C)

Arrhenius Equation:
The rate constant k is related to the temperature (T) and the activation energy (Ea) by the Arrhenius equation:
k = A * e^(-Ea/RT)

Calculating Ea:
1. Take the ratio of rate constants k1 and k2:
k2/k1 = (A * e^(-Ea/RT2)) / (A * e^(-Ea/RT1))
2. Simplify the equation:
e^(-Ea/R * (1/T2 - 1/T1)) = k2/k1
3. Substitute the given values and solve for Ea:
e^(-Ea/R * (1/303 - 1/287)) = 2.2 × 10^–5 / 2.0 × 10^–6
e^(-Ea/8.314 * (0.0033)) = 11
e^(-Ea/0.0274) = 11
-Ea/0.0274 = ln(11)
Ea = -0.0274 * ln(11)
Ea ≈ 26 kcal mol^–1
Therefore, the value of Activation Energy (Ea) is approximately 26 kcal mol^–1. Hence, the correct answer is option 'A'.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rate law is: r = k[Cr(H2O)6]3+ + [SCN–].The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?a)26 kcal mol–1b)2.6 kcal mol–1c)2600 kcal mol–1d)260 kcal mol–1Correct answer is option 'A'. Can you explain this answer?
Question Description
For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rate law is: r = k[Cr(H2O)6]3+ + [SCN–].The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?a)26 kcal mol–1b)2.6 kcal mol–1c)2600 kcal mol–1d)260 kcal mol–1Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rate law is: r = k[Cr(H2O)6]3+ + [SCN–].The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?a)26 kcal mol–1b)2.6 kcal mol–1c)2600 kcal mol–1d)260 kcal mol–1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rate law is: r = k[Cr(H2O)6]3+ + [SCN–].The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?a)26 kcal mol–1b)2.6 kcal mol–1c)2600 kcal mol–1d)260 kcal mol–1Correct answer is option 'A'. Can you explain this answer?.
Solutions for For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rate law is: r = k[Cr(H2O)6]3+ + [SCN–].The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?a)26 kcal mol–1b)2.6 kcal mol–1c)2600 kcal mol–1d)260 kcal mol–1Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rate law is: r = k[Cr(H2O)6]3+ + [SCN–].The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?a)26 kcal mol–1b)2.6 kcal mol–1c)2600 kcal mol–1d)260 kcal mol–1Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rate law is: r = k[Cr(H2O)6]3+ + [SCN–].The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?a)26 kcal mol–1b)2.6 kcal mol–1c)2600 kcal mol–1d)260 kcal mol–1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rate law is: r = k[Cr(H2O)6]3+ + [SCN–].The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?a)26 kcal mol–1b)2.6 kcal mol–1c)2600 kcal mol–1d)260 kcal mol–1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rate law is: r = k[Cr(H2O)6]3+ + [SCN–].The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?a)26 kcal mol–1b)2.6 kcal mol–1c)2600 kcal mol–1d)260 kcal mol–1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice For the reaction:[Cr(H2O)6]3+ + [SCN–] → [Cr(H2O)5NCS]2+ + H2OThe rate law is: r = k[Cr(H2O)6]3+ + [SCN–].The value of k is 2.0 × 10–6 L mol–1 s–1 at 14 °C and 2.2 × 10–5 L mol–1 s–1 at 30 °C. What is the value of Ea?a)26 kcal mol–1b)2.6 kcal mol–1c)2600 kcal mol–1d)260 kcal mol–1Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev