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Calculate the Gibbs free energy for the reaction of conversion of ATP into ADP at 293 Kelvin the change in enthalpy is 19.07 Kcal and the change in entropy is 90 cal per Kelvin.
  • a)
    7.3 cal
  • b)
    -5.3 Kcal
  • c)
    7.3 Kcal
  • d)
    -7.3 Kcal
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Calculate the Gibbs free energy for the reaction of conversion of ATP ...
We have ΔG = ΔH – TΔS; by substituting ΔH = 19.07 kcal and ΔS = 90 cal/K, we get ΔG = 19.07 Kcal – 293(90 cal/K) = 19.07 Kcal – 26.37 Kcal = -7300 cal = -7.3 Kcal. The Gibbs free energy change is -7.3 Kcal.
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Community Answer
Calculate the Gibbs free energy for the reaction of conversion of ATP ...
To calculate the Gibbs free energy (ΔG) for the reaction of the conversion of ATP into ADP at 293 Kelvin, we can use the equation:

ΔG = ΔH - TΔS

where ΔH is the change in enthalpy, ΔS is the change in entropy, and T is the temperature in Kelvin.

Given:
ΔH = 19.07 kcal
ΔS = 90 cal/K
T = 293 K

Substituting the given values into the equation, we have:

ΔG = 19.07 kcal - (293 K)(90 cal/K)

Converting the units to be consistent:

ΔG = 19.07 kcal - (293 K)(0.09 kcal/K)

ΔG = 19.07 kcal - 26.37 kcal

ΔG = -7.3 kcal

Therefore, the Gibbs free energy for the reaction is -7.3 kcal.

Explanation:
- ΔG represents the change in Gibbs free energy, which determines whether a reaction is spontaneous (ΔG < 0)="" or="" non-spontaneous="" (δg="" /> 0).
- ΔH is the change in enthalpy, which is a measure of the heat released or absorbed during a reaction.
- ΔS is the change in entropy, which is a measure of the disorder or randomness of a system.
- T is the temperature in Kelvin, which is necessary for the calculation.

In this case, the negative value of ΔG (-7.3 kcal) indicates that the conversion of ATP into ADP is a spontaneous reaction at 293 Kelvin.
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Calculate the Gibbs free energy for the reaction of conversion of ATP into ADP at 293 Kelvin the change in enthalpy is 19.07 Kcal and the change in entropy is 90 cal per Kelvin.a)7.3 calb)-5.3 Kcalc)7.3 Kcald)-7.3 KcalCorrect answer is option 'D'. Can you explain this answer?
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