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The Inverse function f–1 of f(x) = 2x is
- a)1/2x
- b)x/2
- c)1/x
- d)none of these
Correct answer is option 'B'. Can you explain this answer?
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The Inverse function f–1 of f(x) = 2x isa)1/2xb)x/2c)1/xd)none o...
The inverse function f^-1 of a function f is a function that "undoes" the action of f. In other words, if we apply f to a value x and then apply f^-1 to the result, we should get back the original value x.
Formally, if f is a function from a set X to a set Y, then f^-1 is a function from Y to X such that for any x in X and y in Y:
f(f^-1(y)) = y
f^-1(f(x)) = x
Note that not all functions have inverse functions. A function must be both one-to-one (injective) and onto (surjective) to have an inverse function. A function is one-to-one if it maps each element of X to a unique element of Y, and it is onto if every element of Y is mapped to by at least one element of X.
Formally, if f is a function from a set X to a set Y, then f^-1 is a function from Y to X such that for any x in X and y in Y:
f(f^-1(y)) = y
f^-1(f(x)) = x
Note that not all functions have inverse functions. A function must be both one-to-one (injective) and onto (surjective) to have an inverse function. A function is one-to-one if it maps each element of X to a unique element of Y, and it is onto if every element of Y is mapped to by at least one element of X.
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The Inverse function f–1 of f(x) = 2x isa)1/2xb)x/2c)1/xd)none of theseCorrect answer is option 'B'. Can you explain this answer?
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