Class 9 Exam > Class 9 Questions > A bullet of mass 20 g is horizontally fired ...
Start Learning for Free
A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?
- a)–1.25 ms–1
- b)–1.5 ms–1
- c)1.5 ms–1
- d)2.5 ms–1
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A bullet of mass 20 g is horizontally fired with a velocity of 150 ms...
Recoil Velocity Calculation:
Given:
Mass of bullet (m₁) = 20 g = 0.02 kg
Velocity of bullet (v₁) = 150 m/s
Mass of pistol (m₂) = 2 kg
In this problem, we need to find the recoil velocity of the pistol after firing the bullet.
Using the principle of conservation of momentum, we can solve this problem.
1. Conservation of Momentum:
According to the principle of conservation of momentum, the total momentum before an event is equal to the total momentum after the event, as long as no external forces are acting on the system.
Mathematically, we can express this principle as:
m₁v₁ + m₂v₂ = m₁u₁ + m₂u₂
Where:
m₁ = mass of bullet
v₁ = initial velocity of bullet
m₂ = mass of pistol
v₂ = initial velocity of pistol (recoil velocity)
u₁ = final velocity of bullet (after firing)
u₂ = final velocity of pistol (recoil velocity)
2. Initial and Final Velocities:
Before firing the bullet, the pistol and the bullet are at rest. So, the initial velocities of both the bullet and the pistol are zero.
Therefore, the equation becomes:
(0.02 kg)(150 m/s) + (2 kg)(0) = (0.02 kg)(u₁) + (2 kg)(u₂)
3. Solving for Recoil Velocity:
Simplifying the equation, we get:
3 = 0.02u₁ + 2u₂
Since the bullet is fired horizontally, the final velocity of the bullet (u₁) is in the opposite direction to the initial velocity (v₁). Therefore, u₁ = -150 m/s.
Substituting the values into the equation, we get:
3 = (0.02)(-150) + 2u₂
3 = -3 + 2u₂
6 = 2u₂
u₂ = 6/2 = 3 m/s
Therefore, the recoil velocity of the pistol is 3 m/s in the opposite direction to the bullet's initial velocity.
Given:
Mass of bullet (m₁) = 20 g = 0.02 kg
Velocity of bullet (v₁) = 150 m/s
Mass of pistol (m₂) = 2 kg
In this problem, we need to find the recoil velocity of the pistol after firing the bullet.
Using the principle of conservation of momentum, we can solve this problem.
1. Conservation of Momentum:
According to the principle of conservation of momentum, the total momentum before an event is equal to the total momentum after the event, as long as no external forces are acting on the system.
Mathematically, we can express this principle as:
m₁v₁ + m₂v₂ = m₁u₁ + m₂u₂
Where:
m₁ = mass of bullet
v₁ = initial velocity of bullet
m₂ = mass of pistol
v₂ = initial velocity of pistol (recoil velocity)
u₁ = final velocity of bullet (after firing)
u₂ = final velocity of pistol (recoil velocity)
2. Initial and Final Velocities:
Before firing the bullet, the pistol and the bullet are at rest. So, the initial velocities of both the bullet and the pistol are zero.
Therefore, the equation becomes:
(0.02 kg)(150 m/s) + (2 kg)(0) = (0.02 kg)(u₁) + (2 kg)(u₂)
3. Solving for Recoil Velocity:
Simplifying the equation, we get:
3 = 0.02u₁ + 2u₂
Since the bullet is fired horizontally, the final velocity of the bullet (u₁) is in the opposite direction to the initial velocity (v₁). Therefore, u₁ = -150 m/s.
Substituting the values into the equation, we get:
3 = (0.02)(-150) + 2u₂
3 = -3 + 2u₂
6 = 2u₂
u₂ = 6/2 = 3 m/s
Therefore, the recoil velocity of the pistol is 3 m/s in the opposite direction to the bullet's initial velocity.
Free Test
FREE
| Start Free Test |
Community Answer
A bullet of mass 20 g is horizontally fired with a velocity of 150 ms...
M1 = 20 g = 0.02 kg, m2 = 2 kg.
u1 = 0, u2 = 0 (both pistol and bullet are at rest)
v1 = + 150 ms–1 (the find velocity of the bullet)
let v2 be the recoil velocity of the pistol
according to the law of conservation, total
moment remains the same.
m1u1 + m2u2 = m1v1 + m2v2
.02 × 0 + 2 × 0 = 0.02 × 150 + 2 × v2
0 = 3 + 2v2
⇒ v2 = -3/2 = – 1.5 ms–1
Negative sign indicates that the pistol will
recoil in the opposite direction of the bullet.
Attention Class 9 Students!
To make sure you are not studying endlessly, EduRev has designed Class 9 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 9.
|
Explore Courses for Class 9 exam
|
|
Similar Class 9 Doubts
Top Courses for Class 9View all
A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer?
Question Description
A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer?.
A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer?.
Solutions for A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 9.
Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free.
Here you can find the meaning of A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A bullet of mass 20 g is horizontally fired with a velocity of 150 ms–2 from a pistol of mass 2 kg. What is the recoil velocity of the pistol?a)–1.25 ms–1b)–1.5 ms–1c)1.5 ms–1d)2.5 ms–1Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 9 tests.
|
|
Explore Courses for Class 9 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup