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The work done in lifting a 50 kg of bag from the ground to the head, height of coolie is 200 cm, by the coolie is (assume g = 10 m/s2)
- a)500 J
- b)1000 J
- c)2000 J
- d)10,000 J
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The work done in lifting a 50 kg of bag from the ground to the head, ...
Given:
Mass of the bag, m = 50 kg
Height of the coolie, h = 200 cm = 2 m
Acceleration due to gravity, g = 10 m/s^2
To Find:
The work done by the coolie in lifting the bag.
Solution:
The work done (W) is given by the formula:
W = mgh
where,
m = mass of the object (in kg)
g = acceleration due to gravity (in m/s^2)
h = height (in meters)
Substituting the given values:
m = 50 kg
g = 10 m/s^2
h = 2 m
W = (50 kg) * (10 m/s^2) * (2 m)
W = 1000 J
Hence, the work done by the coolie in lifting the bag is 1000 J.
Explanation:
- The work done in lifting an object is equal to the product of the force applied and the distance over which the force is applied.
- In this case, the coolie is applying a force to lift the bag against the force of gravity.
- The force applied by the coolie is equal to the weight of the bag, which is given by the formula: F = mg, where m is the mass of the bag and g is the acceleration due to gravity.
- The distance over which the force is applied is the height to which the bag is lifted.
- Therefore, the work done by the coolie is equal to the weight of the bag multiplied by the height to which it is lifted.
- Substituting the given values into the formula, we can calculate the work done as 1000 J.
- Hence, the correct answer is option B, 1000 J.
Mass of the bag, m = 50 kg
Height of the coolie, h = 200 cm = 2 m
Acceleration due to gravity, g = 10 m/s^2
To Find:
The work done by the coolie in lifting the bag.
Solution:
The work done (W) is given by the formula:
W = mgh
where,
m = mass of the object (in kg)
g = acceleration due to gravity (in m/s^2)
h = height (in meters)
Substituting the given values:
m = 50 kg
g = 10 m/s^2
h = 2 m
W = (50 kg) * (10 m/s^2) * (2 m)
W = 1000 J
Hence, the work done by the coolie in lifting the bag is 1000 J.
Explanation:
- The work done in lifting an object is equal to the product of the force applied and the distance over which the force is applied.
- In this case, the coolie is applying a force to lift the bag against the force of gravity.
- The force applied by the coolie is equal to the weight of the bag, which is given by the formula: F = mg, where m is the mass of the bag and g is the acceleration due to gravity.
- The distance over which the force is applied is the height to which the bag is lifted.
- Therefore, the work done by the coolie is equal to the weight of the bag multiplied by the height to which it is lifted.
- Substituting the given values into the formula, we can calculate the work done as 1000 J.
- Hence, the correct answer is option B, 1000 J.
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Community Answer
The work done in lifting a 50 kg of bag from the ground to the head, ...
W = m g h
= 50 × 10 × 200/100
= 1000 J
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The work done in lifting a 50 kg of bag from the ground to the head, height of coolie is 200 cm, by the coolie is (assume g = 10 m/s2)a)500 Jb)1000 Jc)2000 Jd)10,000 JCorrect answer is option 'B'. Can you explain this answer?
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