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The figure formed by joining the mid-points of the adjacent sides of a square is 
  • a)
    Parallelogram
  • b)
    Rectangle 
  • c)
    Rhombus
  • d)
    Square 
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The figure formed by joining the mid-points of the adjacent sides of a...
P, Q, R and S are the mid-points of BA, BC, CD and DA respectively.

∴ AP = AS = PB = BQ = QC

∴ In ΔAPS
AP = AS

Similarly
Similarly ∠ASP = ∠APS =∠BPQ = ∠BQP = ∠CQR
= ∠CRQ = ∠DSR = ∠DRS = 45°
Now ∠P + ∠ASP + ∠APS = 180°
⇒ ∠P = 90°
Similarly,
∠P = ∠Q = ∠R = ∠S = 90°
∴ PQRS is a parallelogram having each of its angles = 90°
Now
using midpoint theorem in DABC and DACD
SR = PQ = 1/2 AC, and in DS ABD and BDC

∴ SP = PQ = QR = RS
∴ PQRS is a square
Free Test
Community Answer
The figure formed by joining the mid-points of the adjacent sides of a...
Explanation:
To understand why the figure formed by joining the mid-points of the adjacent sides of a square is a square, let's consider a square ABCD.

Definition:
- A square is a quadrilateral with all four sides equal in length and all four angles equal to 90 degrees.

Construction:
- Let P, Q, R, and S be the midpoints of AB, BC, CD, and DA respectively.
- Join PQ, QR, RS, and SP.

Proof:
- To prove that the figure formed by joining the mid-points of the adjacent sides of a square is a square, we need to show that all four sides are equal in length and all four angles are equal to 90 degrees.

All four sides are equal in length:
- In a square ABCD, all four sides are equal. Therefore, AB = BC = CD = DA.
- In the figure formed by joining the mid-points of the adjacent sides of the square, we have PQ || AB, QR || BC, RS || CD, and SP || DA.
- By the midpoint theorem, we know that PQ = QR = RS = SP.
- Therefore, all four sides of the figure formed by joining the mid-points are equal in length.

All four angles are equal to 90 degrees:
- In a square ABCD, all four angles are equal to 90 degrees.
- In the figure formed by joining the mid-points of the adjacent sides of the square, we can see that PQ is parallel to AB and QR is parallel to BC.
- Since AB and BC are perpendicular to each other, PQ and QR are also perpendicular to each other.
- Similarly, RS is perpendicular to CD and SP is perpendicular to DA.
- Therefore, all four angles of the figure formed by joining the mid-points are equal to 90 degrees.

Conclusion:
- Since all four sides of the figure formed by joining the mid-points of the adjacent sides of a square are equal in length and all four angles are equal to 90 degrees, the figure is a square.
- Hence, option 'D', square, is the correct answer.
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The figure formed by joining the mid-points of the adjacent sides of a square isa)Parallelogramb)Rectanglec)Rhombusd)SquareCorrect answer is option 'D'. Can you explain this answer?
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