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Point O is the point of intersection of AC and BD of parallelogram ABCD and, also, PQ ∥ AD, then,
  • a)
    ar(ABCD) = 2 × (ar(PQDA)) 
  • b)
    ar (PQDA) = ar(ABCD) 
  • c)
    ar(POB) = ar(AOD) 
  • d)
    ar(PQDA) = ar(AOB) 
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Point O is the point of intersection of AC and BD of parallelogram ABC...
∵ O lies in mid of the parallelogram. 
∴ PQ divides parallelogram in two parts of equal areas.
∴ ar (PQDA) = 1/2 ar (ABCD) 
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Point O is the point of intersection of AC and BD of parallelogram ABCD and, also,PQ AD, then,a)ar(ABCD) = 2 × (ar(PQDA))b)ar (PQDA) = ar(ABCD)c)ar(POB) = ar(AOD)d)ar(PQDA) = ar(AOB)Correct answer is option 'A'. Can you explain this answer?
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