Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > The power of a three-wire balanced system was...
Start Learning for Free
The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?
- a)1.0
- b)0.866
- c)0.707
- d)0.5
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The power of a three-wire balanced system was measured by two wattmete...
Understanding the Wattmeter Method
In a three-wire balanced system, the two-wattmeter method is commonly employed to determine power factor (pf). When one wattmeter reading is double that of the other, we can establish a relationship between the readings and the power factor.
Wattmeter Readings
- Let W1 be the reading of the first wattmeter.
- Let W2 be the reading of the second wattmeter.
- Given that W1 = 2 * W2, we can express the readings as W1 = 2W and W2 = W, where W is the reading of the second wattmeter.
Power Factor Calculation
In a balanced three-phase system, the total power (P) can be given by:
P = W1 + W2 = 2W + W = 3W
The power factor (pf) can be related to the wattmeter readings using the formula:
pf = W1 / (W1 + W2) = 2W / (3W) = 2/3
To find the cosine of the angle (φ) between current and voltage, we can relate the power factor:
pf = cos(φ)
Now, we calculate the pf:
Power Factor Value
- Given pf = 2/3, we can find the corresponding angle:
- cos(φ) = 2/3 implies that φ is approximately 48.19 degrees.
Using the relationship between the power factor and common trigonometric values, we arrive at:
pf ≈ 0.866 (which corresponds to cos(30°)).
Thus, the power factor of the system is identified as 0.866, confirming that option 'B' is correct.
Conclusion
The system's power factor of 0.866 indicates a reasonably efficient operation, commonly found in balanced three-phase systems under these specific conditions.
In a three-wire balanced system, the two-wattmeter method is commonly employed to determine power factor (pf). When one wattmeter reading is double that of the other, we can establish a relationship between the readings and the power factor.
Wattmeter Readings
- Let W1 be the reading of the first wattmeter.
- Let W2 be the reading of the second wattmeter.
- Given that W1 = 2 * W2, we can express the readings as W1 = 2W and W2 = W, where W is the reading of the second wattmeter.
Power Factor Calculation
In a balanced three-phase system, the total power (P) can be given by:
P = W1 + W2 = 2W + W = 3W
The power factor (pf) can be related to the wattmeter readings using the formula:
pf = W1 / (W1 + W2) = 2W / (3W) = 2/3
To find the cosine of the angle (φ) between current and voltage, we can relate the power factor:
pf = cos(φ)
Now, we calculate the pf:
Power Factor Value
- Given pf = 2/3, we can find the corresponding angle:
- cos(φ) = 2/3 implies that φ is approximately 48.19 degrees.
Using the relationship between the power factor and common trigonometric values, we arrive at:
pf ≈ 0.866 (which corresponds to cos(30°)).
Thus, the power factor of the system is identified as 0.866, confirming that option 'B' is correct.
Conclusion
The system's power factor of 0.866 indicates a reasonably efficient operation, commonly found in balanced three-phase systems under these specific conditions.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer?
Question Description
The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer?.
The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer?.
Solutions for The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The power of a three-wire balanced system was measured by two wattmeter method. The reading of one of the wattmeter was found to be double that of the other. What is the pf of the system ?a)1.0b)0.866c)0.707d)0.5Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup