An iron ring of mean circumference of 50 cm has an air gap of 2mm cut in it. It has circular cross section with area of 5cm2 . It carries a coil wound with 600 turns uniformly. The relative permeability of iron is 580. If coil carries a current of 2 A find flux in air gap.?

Question

Answer

Calculation of Flux in Air Gap

Given Parameters:

Mean circumference of iron ring = 50 cm

Air gap in the ring = 2 mm

Circular cross-section area of the ring = 5 cm²

Number of turns in the coil = 600

Current flowing through the coil = 2 A

Relative permeability of iron = 580

Calculation of Magnetic Flux in the Air Gap:

The magnetic flux in the air gap is given by the formula:

Φ = (N * I * μ_r * A) / (2 * g)

Where,

N = Number of turns in the coil

I = Current flowing through the coil

μ_r = Relative permeability of iron

A = Cross-sectional area of the iron ring

g = Air gap in the iron ring

Substituting the given values in the formula:

Φ = (600 * 2 * 580 * 5) / (2 * 0.2)

Φ = 348000 Weber

Explanation:

The given question is related to magnetic flux in a ring with an air gap. The formula for magnetic flux in the air gap is given by Φ = (N * I * μ_r * A) / (2 * g), where N is the number of turns in the coil, I is the current flowing through the coil, μ_r is the relative permeability of iron, A is the cross-sectional area of the iron ring, and g is the air gap in the iron ring.

Substituting the given values in the formula, we get the value of magnetic flux in the air gap as 348000 Weber.

Answer

Yes

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