A piece of metal at 400K with henticappecity of 1000K is pushed into a...
Given information:
- Initial temperature of the metal (T1) = 400K
- Henticappecity of the metal (C) = 1000K
- Temperature of the heat bath (T2) = 100K
To find:
Change in entropy of the universe.
Solution:
1. Change in entropy of the metal:
The change in entropy of the metal can be calculated using the formula:
ΔS_metal = C * ln(T2/T1)
Where C is the henticappecity of the metal, T1 is the initial temperature, and T2 is the final temperature.
Plugging in the given values:
ΔS_metal = 1000K * ln(100K/400K)
ΔS_metal = 1000K * ln(0.25)
ΔS_metal = 1000K * (-1.386)
Therefore, ΔS_metal = -1386JK^(-1)
2. Change in entropy of the heat bath:
The change in entropy of the heat bath can be calculated using the formula:
ΔS_bath = -Q/T2
Where Q is the heat transferred to the heat bath and T2 is the temperature of the heat bath.
Since the metal is being cooled, Q will be negative.
3. Change in entropy of the universe:
The change in entropy of the universe is given by the sum of the change in entropy of the metal and the change in entropy of the heat bath:
ΔS_universe = ΔS_metal + ΔS_bath
Since the heat bath is at a lower temperature than the metal, the change in entropy of the heat bath will be positive. However, the magnitude of the change in entropy of the metal is greater, resulting in a net decrease in entropy.
Final Answer:
The change in entropy of the universe is -1386JK^(-1) (option a).