250/125 V, 5 KVA single phase transformer has primary resistance of 0....
Calculation of Regulation
Regulation refers to the percentage drop in voltage from no-load to full-load conditions. It is calculated using the formula:
% Regulation = (Vno-load - Vfull-load) / Vfull-load x 100%
Where Vno-load is the secondary voltage at no-load and Vfull-load is the secondary voltage at full-load.
Given data:
- Primary voltage (V1) = 250 V
- Secondary voltage (V2) = 125 V
- Power rating (S) = 5 KVA
- Primary resistance (R1) = 0.2 Ω
- Primary reactance (X1) = 0.75 Ω
- Secondary resistance (R2) = 0.05 Ω
- Secondary reactance (X2) = 0.2 Ω
- Power factor (pf) = 0.8 leading
First, we need to calculate the equivalent impedance of the transformer referred to the primary side:
Zeq = (R1 + jX1) + [(R2 + jX2) / (k^2)]
Where k is the turns ratio = V1 / V2
Substituting the given values:
k = V1 / V2 = 250 / 125 = 2
Zeq = (0.2 + j0.75) + [(0.05 + j0.2) / (2^2)] = 0.2125 + j0.8875 Ω
Next, we can calculate the current in the secondary winding:
I2 = S / V2 = 5 x 10^3 / 125 = 40 A
Since the power factor is leading, the angle of the current (θ) is negative:
θ = cos^-1(pf) = cos^-1(0.8) = -36.87°
Hence, the current can be represented as:
I2 = 40 ∠-36.87° A
Now, we can find the voltage drop in the equivalent impedance:
Vdrop = Zeq x I2 = (0.2125 + j0.8875) x 40 ∠-36.87° = 8.5 ∠53.13° V
The secondary voltage under full-load conditions is given by:
V2(full-load) = V2 - Vdrop = 125 - 8.5 = 116.5 V
Therefore, the percentage regulation is:
% Regulation = (125 - 116.5) / 116.5 x 100% = 7.27%
Calculation of Secondary Terminal