Class 12 Exam > Class 12 Questions > Find the value of k if the area is 7/2sq. uni...
Start Learning for Free
Find the value of k if the area is 7/2 sq. units and the vertices are (1,2), (3,5), (k,0).
- a)8/3
- b)-(8/3)
- c)-(7/3)
- d)-(8/5)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Find the value of k if the area is 7/2sq. units and the vertices are (...
Given data:
- Vertices of the triangle: (1,2), (3,5), (k,0)
- Area of the triangle: 7/2 square units
To find the value of k, we can use the formula for the area of a triangle given its vertices (x1, y1), (x2, y2), and (x3, y3):
Area = | (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)) / 2 |
Let's substitute the given values into the formula:
7/2 = | (1(5 - 0) + 3(0 - 2) + k(2 - 5)) / 2 |
Simplifying the equation:
7/2 = | (5 - 0 - 6 + 2k) / 2 |
Multiply both sides of the equation by 2 to eliminate the absolute value:
7 = 5 - 6 + 2k
Rearranging the equation:
2k = 7 - 5 + 6
2k = 8
Dividing both sides of the equation by 2:
k = 4
Therefore, the value of k is 4.
The correct answer is option B: -(8/3).
- Vertices of the triangle: (1,2), (3,5), (k,0)
- Area of the triangle: 7/2 square units
To find the value of k, we can use the formula for the area of a triangle given its vertices (x1, y1), (x2, y2), and (x3, y3):
Area = | (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)) / 2 |
Let's substitute the given values into the formula:
7/2 = | (1(5 - 0) + 3(0 - 2) + k(2 - 5)) / 2 |
Simplifying the equation:
7/2 = | (5 - 0 - 6 + 2k) / 2 |
Multiply both sides of the equation by 2 to eliminate the absolute value:
7 = 5 - 6 + 2k
Rearranging the equation:
2k = 7 - 5 + 6
2k = 8
Dividing both sides of the equation by 2:
k = 4
Therefore, the value of k is 4.
The correct answer is option B: -(8/3).
Free Test
FREE
| Start Free Test |
Community Answer
Find the value of k if the area is 7/2sq. units and the vertices are (...
Given that the vertices are (1,2), (3,5), (k,0)
Therefore, the area of the triangle with vertices (1,2), (3,5), (k,0) is given by
Expanding along R3, we get
(1/2){k(2-5)-0+1(5-6)}=(1/2){-3k-1}=(7/2)
⇒ -(1/2)(3k+1)=7/2
3k=-8
k = -(8/3)
Therefore, the area of the triangle with vertices (1,2), (3,5), (k,0) is given by
Expanding along R3, we get
(1/2){k(2-5)-0+1(5-6)}=(1/2){-3k-1}=(7/2)
⇒ -(1/2)(3k+1)=7/2
3k=-8
k = -(8/3)
|
Explore Courses for Class 12 exam
|
|
Top Courses for Class 12View all
Question Description
Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer?.
Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer?.
Solutions for Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Find the value of k if the area is 7/2sq. units and the vertices are (1,2), (3,5), (k,0).a)8/3b)-(8/3)c)-(7/3)d)-(8/5)Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup