Class 12 Exam > Class 12 Questions > At NTP, the solubility of natural gas in wate...
Start Learning for Free
At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?
- a)8 kN/m2
- b)7.90 x 10-3 Pa
- c)71.36 bar
- d)105 mmHg
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg o...
Given,
Solubility of natural gas, S = 0.8 mole of gas/kg of water = 0.8 molal
Hence, moles of natural gas in mixture, nNG = 0.8 mole
At NTP, pressure, PNG = 1.01325 bar
Number of moles of water in 1000 g, nw = mass/molar mass
nw = 1000g / (18g/mole) = 55.56 mole
Mole fraction of natural gas in the mixture, XNG = nNG/ (nNG + nw)
XNG = 0.8/(0.8 + 55.56) = 0.0142
Using Henry’s law PNG = KH x XNG
KH = PNG/XNG = 1.01325 bar/0.0142 = 71.36 bar.
Solubility of natural gas, S = 0.8 mole of gas/kg of water = 0.8 molal
Hence, moles of natural gas in mixture, nNG = 0.8 mole
At NTP, pressure, PNG = 1.01325 bar
Number of moles of water in 1000 g, nw = mass/molar mass
nw = 1000g / (18g/mole) = 55.56 mole
Mole fraction of natural gas in the mixture, XNG = nNG/ (nNG + nw)
XNG = 0.8/(0.8 + 55.56) = 0.0142
Using Henry’s law PNG = KH x XNG
KH = PNG/XNG = 1.01325 bar/0.0142 = 71.36 bar.
Free Test
FREE
| Start Free Test |
Community Answer
At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg o...
The Henry's Law constant (H) is a measure of the solubility of a gas in a liquid and is defined as the ratio of the concentration of the gas in the liquid phase to the partial pressure of the gas in the gaseous phase at equilibrium.
In this case, the Henry's Law constant (H) can be calculated using the following equation:
H = (concentration of gas in liquid phase) / (partial pressure of gas in gaseous phase)
Given that the solubility of natural gas in water is 0.8 mole of gas per kg of water, we can assume that the concentration of gas in the liquid phase is 0.8 mol/kg.
At NTP (Normal Temperature and Pressure), the partial pressure of the gas is 1 atm.
Therefore, the Henry's Law constant (H) can be calculated as:
H = (0.8 mol/kg) / (1 atm)
H = 0.8 mol/kg/atm
So, the Henry's Law constant for the solubility of natural gas in water at NTP is 0.8 mol/kg/atm.
In this case, the Henry's Law constant (H) can be calculated using the following equation:
H = (concentration of gas in liquid phase) / (partial pressure of gas in gaseous phase)
Given that the solubility of natural gas in water is 0.8 mole of gas per kg of water, we can assume that the concentration of gas in the liquid phase is 0.8 mol/kg.
At NTP (Normal Temperature and Pressure), the partial pressure of the gas is 1 atm.
Therefore, the Henry's Law constant (H) can be calculated as:
H = (0.8 mol/kg) / (1 atm)
H = 0.8 mol/kg/atm
So, the Henry's Law constant for the solubility of natural gas in water at NTP is 0.8 mol/kg/atm.
|
Explore Courses for Class 12 exam
|
|
At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer?
Question Description
At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer?.
At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer?.
Solutions for At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice At NTP, the solubility of natural gas in water is 0.8 mole of gas/kg of water. What is the Henry’s law constant for natural gas?a)8 kN/m2b)7.90 x 10-3 Pac)71.36 bard)105 mmHgCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup