Direction: Answer the question on the basis of the information given below.There are four equal sized containers - A, B, C and D - that have alcohol and water in different ratios. A contains alcohol and water in the ratio 4 : 3. B contains water and alcohol in the ratio 4 : 5. In C the quantity of alcohol is half the quantity of water. D contains alcohol and water in the ratio 2 : 5. Q. If 18 litres of mixture from B and 6 litres of mixture from C are mixed, then find the quantity of alcohol in 600 ml of the final mixture.a)350 mlb)250 mlc)300 mld)240 mlCorrect answer is option 'C'. Can you explain this answer?

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Direction: Answer the question on the basis of the information given below.

There are four equal sized containers - A, B, C and D - that have alcohol and water in different ratios.

A contains alcohol and water in the ratio 4 : 3.

B contains water and alcohol in the ratio 4 : 5.

In C the quantity of alcohol is half the quantity of water.

D contains alcohol and water in the ratio 2 : 5.

Q. If 18 litres of mixture from B and 6 litres of mixture from C are mixed, then find the quantity of alcohol in 600 ml of the final mixture.

a)
350 ml
b)
250 ml
c)
300 ml
d)
240 ml

Correct answer is option 'C'. Can you explain this answer?

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Direction: Answer the question on the basis of the information given ...

To find the quantity of alcohol in 600 ml of the final mixture, we need to consider the alcohol-water ratios of the individual containers and the amounts of mixtures being mixed. Let's break down the problem step by step:

Step 1: Determine the amount of alcohol in the 18 liters of mixture from container B.
Container B has a water-alcohol ratio of 4:5. This means that for every 4 parts of water, there are 5 parts of alcohol.
The total ratio is 4 + 5 = 9 parts.
Since we have 18 liters of mixture from container B, we can calculate the amount of alcohol in it as follows:
Alcohol in B = (5/9) * 18 liters

Step 2: Determine the amount of alcohol in the 6 liters of mixture from container C.
Container C has alcohol that is half the quantity of water. Let's assume the quantity of water in container C is x liters. Then the quantity of alcohol in container C would be (1/2) * x liters.
Since we have 6 liters of mixture from container C, we can set up the following equation:
(1/2) * x = 6 liters
Solving this equation, we find that x = 12 liters.
So, the quantity of alcohol in container C is (1/2) * 12 liters.

Step 3: Calculate the total amount of alcohol in the mixture.
To find the total amount of alcohol in the mixture, we add the amounts of alcohol from containers B and C:
Total alcohol = (5/9) * 18 liters + (1/2) * 12 liters

Step 4: Find the quantity of alcohol in 600 ml of the final mixture.
We know that the total alcohol is in terms of liters, so we need to convert 600 ml to liters:
600 ml = 600/1000 liters = 0.6 liters
To find the quantity of alcohol in 0.6 liters of the final mixture, we can set up the following proportion:
Total alcohol / Total mixture = Alcohol in 0.6 liters / 0.6 liters
Solving for Alcohol in 0.6 liters, we find:
Alcohol in 0.6 liters = (Total alcohol / Total mixture) * 0.6 liters

Step 5: Substitute the values to calculate the quantity of alcohol in 600 ml of the final mixture.
Substituting the values from Step 3 into the equation from Step 4, we get:
Alcohol in 0.6 liters = ((5/9) * 18 liters + (1/2) * 12 liters) / (18 liters + 12 liters) * 0.6 liters

Calculating this expression, we find that the quantity of alcohol in 600 ml of the final mixture is approximately 300 ml.

Therefore, the correct answer is option C) 300 ml.

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Direction: Answer the question on the basis of the information given ...

In 18 litres of mixture from B the quantity of alcohol and water are 10 litres and 8 litres respectively.

In 6 litres of mixture from C the quantity of alcohol and water are 2 litres and 4 litres respectively.

The ratio of alcohol to water in the final mixture is 12 : 12 = 1 : 1.

Hence, in 600 ml of the final mixture the quantity of alcohol will be 300 ml.

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Direction: Answer the question on the basis of the information given below.There are four equal sized containers - A, B, C and D - that have alcohol and water in different ratios. A contains alcohol and water in the ratio 4 : 3. B contains water and alcohol in the ratio 4 : 5. In C the quantity of alcohol is half the quantity of water. D contains alcohol and water in the ratio 2 : 5. Q. If 18 litres of mixture from B and 6 litres of mixture from C are mixed, then find the quantity of alcohol in 600 ml of the final mixture.a)350 mlb)250 mlc)300 mld)240 mlCorrect answer is option 'C'. Can you explain this answer?

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