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In a process temperature and volume of 1 mole of an ideal moniatomic gas are varied according to the relation VT=k where k is a constant. In this process, the temperature of gas is increased by delta T. The amount of the heat absorbed by gas is (whare R is a gas constant) (A) 1/2 kR deltaT (B) 2k/3 delta T (C) 1/2 R deltaT (D) 3/2 R deltaT?
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In a process temperature and volume of 1 mole of an ideal moniatomic gas are varied according to the relation VT=k where k is a constant. In this process, the temperature of gas is increased by delta T. The amount of the heat absorbed by gas is (whare R is a gas constant) (A) 1/2 kR deltaT (B) 2k/3 delta T (C) 1/2 R deltaT (D) 3/2 R deltaT?
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In a process temperature and volume of 1 mole of an ideal moniatomic gas are varied according to the relation VT=k where k is a constant. In this process, the temperature of gas is increased by delta T. The amount of the heat absorbed by gas is (whare R is a gas constant) (A) 1/2 kR deltaT (B) 2k/3 delta T (C) 1/2 R deltaT (D) 3/2 R deltaT? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about In a process temperature and volume of 1 mole of an ideal moniatomic gas are varied according to the relation VT=k where k is a constant. In this process, the temperature of gas is increased by delta T. The amount of the heat absorbed by gas is (whare R is a gas constant) (A) 1/2 kR deltaT (B) 2k/3 delta T (C) 1/2 R deltaT (D) 3/2 R deltaT? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a process temperature and volume of 1 mole of an ideal moniatomic gas are varied according to the relation VT=k where k is a constant. In this process, the temperature of gas is increased by delta T. The amount of the heat absorbed by gas is (whare R is a gas constant) (A) 1/2 kR deltaT (B) 2k/3 delta T (C) 1/2 R deltaT (D) 3/2 R deltaT?.
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