To calculate the time required to hydrolyze 19.8 grams of ethyl acetate, we need to use the rate constant and the stoichiometry of the reaction.

1. Determine the molar mass of ethyl acetate:
The molar mass of ethyl acetate (C4H8O2) can be calculated by adding the atomic masses of carbon (12.01 g/mol), hydrogen (1.01 g/mol), and oxygen (16.00 g/mol) together:
Molar mass of ethyl acetate = (4 * 12.01 g/mol) + (8 * 1.01 g/mol) + (2 * 16.00 g/mol) = 88.11 g/mol

2. Calculate the number of moles of ethyl acetate:
Using the formula:
moles = mass / molar mass
we can find the number of moles of ethyl acetate in 19.8 grams:
moles of ethyl acetate = 19.8 g / 88.11 g/mol = 0.224 moles

3. Use the stoichiometry of the reaction:
From the balanced chemical equation for the hydrolysis of ethyl acetate, we know that 1 mole of ethyl acetate produces 1 mole of product. Therefore, the moles of product formed will be equal to the moles of ethyl acetate:

moles of product = 0.224 moles

4. Use the rate constant and the rate equation:
The rate equation for the hydrolysis of ethyl acetate is given by:
Rate = k * [ethyl acetate]

where k is the rate constant. From the given information, the rate constant is 2.303 × 10^-4.

5. Calculate the time required:
To calculate the time required for the reaction, we can rearrange the rate equation and solve for time:

Rate = k * [ethyl acetate]
Time = moles of product / rate
Time = 0.224 moles / (2.303 × 10^-4 s^-1)
Time ≈ 973.24 seconds

Therefore, it would take approximately 973.24 seconds to hydrolyze 19.8 grams of ethyl acetate.

To summarize:
- Molar mass of ethyl acetate is 88.11 g/mol.
- The number of moles of ethyl acetate is 0.224 moles.
- The rate constant (k) is 2.303 × 10^-4 s^-1.
- The time required to hydrolyze 19.8 grams of ethyl acetate is approximately 973.24 seconds.