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What will be the output of the following C++ code?
    #include <iostream>
    using namespace std;
    void fun(int x, int y)
    {
        x = 20;
        y = 10;
    }
    int main()
    {
        int x = 10;
        fun(x, x);
        cout << x;
        return 0;
    }
  • a)
    10
  • b)
    20
  • c)
    compile time error
  • d)
    30
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following C++ code? #include <iostr...
In this program, we called by value so the value will not be changed, So the output is 10
Output:
$ g++ fun.cpp
$ a.out
10
Free Test
Community Answer
What will be the output of the following C++ code? #include <iostr...


Explanation:

- Function fun:
- The function `fun` takes two parameters `x` and `y` by value.
- Inside the function, the values of `x` and `y` are changed to 20 and 10 respectively.

- main function:
- In the `main` function, an integer variable `x` is declared and initialized to 10.
- The `fun` function is called with `x` as both arguments.
- However, since the arguments are passed by value, the original value of `x` in `main` remains unchanged.

- Output:
- After calling the `fun` function, the value of `x` remains 10 in the `main` function.
- Therefore, when `x` is printed using `cout`, the output will be `10`.

Therefore, the output of the given C++ code will be:


10
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What will be the output of the following C++ code? #include <iostream> using namespace std; void fun(int x, int y) { x = 20; y = 10; } int main() { int x = 10; fun(x, x); cout << x; return 0; }a)10b)20c)compile time errord)30Correct answer is option 'A'. Can you explain this answer?
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