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What will be the output of the following C++ code?
    #include <stdio.h>
    #include<iostream>
    using namespace std;
    int main()
    {
        int a = 5, b = 10, c = 15;
        int arr[3] = {&a, &b, &c};
        cout << *arr[*arr[1] - 8];
        return 0;
    }
  • a)
    15
  • b)
    18
  • c)
    garbage value
  • d)
    compile time error
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following C++ code? #include <stdio...
The conversion is invalid in this array. So it will arise error. The following compilation error will be raised:
cannot convert from ‘int *’ to ‘int’
This is because &a, &b and &c represent int* whereas the array defined is of int type.
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Community Answer
What will be the output of the following C++ code? #include <stdio...

Explanation:

- The code provided is trying to create an integer array `arr` with three elements, where each element points to the variables `a`, `b`, and `c`.
- In C++, when we declare an array of integers, we should only use integer values within the curly braces. However, in this code, the elements of the array are pointers to integers.
- This will result in a compile-time error because the compiler expects integer values, not pointers.
- Therefore, the code will not compile, and the output will be a compile-time error.

Therefore, the correct answer is compile time error.
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What will be the output of the following C++ code? #include <stdio.h> #include<iostream> using namespace std; int main() { int a = 5, b = 10, c = 15; int arr[3] = {&a, &b, &c}; cout << *arr[*arr[1] - 8]; return 0; }a)15b)18c)garbage valued)compile time errorCorrect answer is option 'D'. Can you explain this answer?
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