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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
void fun(int x, int y)
{
x = 20;
y = 10;
}
int main()
{
int x = 10;
fun(x, x);
cout << x;
return 0;
}
using namespace std;
void fun(int x, int y)
{
x = 20;
y = 10;
}
int main()
{
int x = 10;
fun(x, x);
cout << x;
return 0;
}
- a)10
- b)20
- c)compile time error
- d)30
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
What will be the output of the following C++ code? #include <iostr...
In this program, we called by value so the value will not be changed, So the output is 10
Output:
$ g++ fun.cpp
$ a.out
10
Output:
$ g++ fun.cpp
$ a.out
10
Most Upvoted Answer
What will be the output of the following C++ code? #include <iostr...
Explanation:
- Function fun:
- The function `fun` takes two parameters `x` and `y` by value.
- Inside the function, the values of `x` and `y` are changed to 20 and 10 respectively.
- main function:
- In the `main` function, an integer variable `x` is declared and initialized to 10.
- The `fun` function is called with `x` as both arguments.
- However, since the arguments are passed by value, the original value of `x` in `main` remains unchanged.
- Output:
- After calling the `fun` function, the value of `x` remains 10 in the `main` function.
- Therefore, when `x` is printed using `cout`, the output will be `10`.
Therefore, the output of the given C++ code will be:
10
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Community Answer
What will be the output of the following C++ code? #include <iostr...
In this program, we called by value so the value will not be changed, So the output is 10
Output:
$ g++ fun.cpp
$ a.out
10
Output:
$ g++ fun.cpp
$ a.out
10
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