What will be the output of the following C++ code?
#include <iostream>
#include <string>
using namespace std;
int main ()
{
string str;
string str2="Steve jobs";
string str3="He founded apple";
str.append(str2);
str.append(str3, 6, 3);
str.append(str3.begin() + 6, str3.end());
str.append(5,0x2e);
cout << str << '\n';
return 0;
}

Question

What will be the output of the following C++ code?

#include <iostream>
#include <string>
using namespace std;
int main ()
{
string str;
string str2="Steve jobs";
string str3="He founded apple";
str.append(str2);
str.append(str3, 6, 3);
str.append(str3.begin() + 6, str3.end());
str.append(5,0x2e);
cout << str << '\n';
return 0;
}

a)
Steve jobs
b)
He founded apple
c)
Steve
d)
Steve jobsndended apple…..

Correct answer is option 'D'. Can you explain this answer?

Answer

In this program, We are adding characters to the string, So the output will as follows after addition of characters.
Output:

$ g++ str.cpp
$ a.out
Steve jobsndended apple.....

Answer

Explanation:
- String Initialization:
- Two strings `str2` and `str3` are initialized with values 'Steve jobs' and 'He founded apple' respectively.
- Appending:
- `str.append(str2);` appends the content of `str2` to the end of `str`.
- `str.append(str3, 6, 3);` appends 3 characters from index 6 of `str3` to `str`.
- `str.append(str3.begin() + 6, str3.end());` appends the rest of the characters from index 6 of `str3` to `str`.
- `str.append(5,0x2e);` appends 5 occurrences of the character represented by 0x2e (which is '.') to `str`.
- Output:
- After all the append operations, the final content of `str` will be 'Steve jobs...nded apple'.
Therefore, the output of the code will be:
Steve jobs...nded apple

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